Explain how to estmate 586- 321 two different ways

Answers

Answer 1

Answer: Estimating Sums and Differences: Explain how to estimate 368 + 231 two different ways. Explain how to estimate 586 – 321 two different ways. Why is it important to estimate before solving a problem? Which gives an estimate that is closer to the exact sum: rounding to the nearest ten or rounding to the nearest hundred

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Change 12/18 in thirds

Answers

12/18 = 2(6)/3(6) = 2/3 is your reduced answer.

4/6=2/3
Hope this helps :)

A recipe for trail mix uses 7 ounces of almonds with 5 ounces of raisins. How many ounces of almonds would be in a one pound bag of this trail mix

Answers

The number of ounces of almonds would be in a one pound bag of this trail 9 1/3 ounces

Given:

Almonds = 7 ounces

Raisins = 5 ounces

Ratio of almonds to raisins = 7 : 5

Total ratio = 7 + 5

= 12

Total mixture = 1 pounds

= 16 ounces

1 pound = 16 ounces

Quantity of almonds in 1 pound mix = Ratio of almonds / Total ratio × Total mixture

= 7/12 × 16

= (7 × 16) / 12

= 112 / 12

= 9 1/3 ounces

Therefore, number of ounces of almonds would be in a one pound bag of this trail is 9 1/3 ounces

brainly.com/question/12527870

Answer: In your mix, you have 7 ounces of almonds and 5 ounces of raisins, which adds to 7 + 5 = 12 ounces of mix.

Because we want to know the proportion of almonds, then if 12 is the total amount, 7/12 is the proportion of almonds in the mix, this is 7/12 = 0.583

In one pound there are 16 ounces, so in one pound of mix you have 16 ounces of it. Now you know the proportion of almonds in a mix is of 0.583, then you multiply this by the ounces of mix and you get the ounces of almonds in it:

0.583*16 = 9.33

then you have 9.33 ounces of almonds in one pound of mix.

meyer has 0.64 GB of space remaining on his ipod.he wants to download a pedometer app (0.24 GB), a photo app (0.403 GB), and a math app (0.3 GB).which combinations of apps can he download? explain your thinking

Answers

He can either download both the pedometer and the math apps,
or he can download only the photo app and no more.

Pedometer + math = 0.54 GB. Fits in 0.64 GB.

Photo = 0.403 GB. Fits in 0.64 GB, but only 0.237 GB left.
Not enough for pedometer (0.24)
or math (0.3) .

The possible combination in which the app can be downloaded in ipod is $\boxed{\text{pedometer app}+\text{math app}}$ or $\boxed{\text{Photo app}}$ .

Further explanation:

The total memory space available in the ipod is $0.64\text{ GB}$ .

The memory space required for the pedometer app is $0.24\text{ GB}$ .

The memory space required for a photo app is $0.403\text{ GB}$ .

The memory space required for a math app is $0.4\text{ GB}$ .

As per teh question meyer wants to download the app as mentioned above in his ipod.

So, in order to download the app the most important point is that the total memory space available in the ipod should no be less than the memory space required for all the apps.

The objective is to determine the combination in which the different app can be stored in the ipod.

Consider three cases for the given question.

Case 1:

Consider that all the three apps are needed to be downloaded in the ipod.

If all the three apps are required to be downloaded then the total memory space required is calculated as follows:

$\boxed{0.24+0.403+0.3=0.943}$

As per the above calculation it is concluded that the all the three apps requires a memory space of $0.943\text{ GB}$ .

Since, the total free memory space available in the ipod is $0.64\text{ GB}$ and $0.943>0.64$ so, this case is not possible.

Therefore, it is not possible to download all the three apps in ipod.

Case 2:

Consider that only pedometer app and a photo app is required to be downloaded.

The memory space required by pedometer app and a photo app is calculated as follows:

$\boxed{0.24+0.403=0.643}$

As per the above calculation it is concluded that the photo app and pedometer app requires a memory space of $0.643\text{ GB}$ .

Since, the total free memory space available in the ipod is $0.64\text{ GB}$ and $0.643>0.64$ so, this case is not possible.

Therefore, it is not possible to download pedometer app and a photo app in ipod.

Case 3:

Consider that only pedometer app and a math app is required to be downloaded.

The memory space required by pedometer app and a math app is calculated as follows:

$\boxed{0.24+0.3=0.54}$

As per the above calculation it is concluded that a math app and a pedometer app requires a memory space of $0.54\text{ GB}$ .

Since, the total free memory space available in the ipod is $0.64\text{ GB}$ and $0.64>0.54$ so, this case is possible.

Therefore, it is possible to download pedometer app and a math app in ipod.

Case 4:

Consider that only a photo app and a math app is required to be downloaded.

The memory space required by math app and a photo app is calculated as follows:

$\boxed{0.3+0.403=0.703}$

As per the above calculation it is concluded that the photo app and pedometer app requires a memory space of $0.703\text{ GB}$ .

Since, the total free memory space available in the ipod is $0.64\text{ GB}$ and $0.703>0.64$ so, this case is not possible.

Therefore, it is not possible to download math app and a photo app in ipod.

This implies that either meyer can download pedometer app and math app or only a photo app.

Thus, the possible combination in which the app can be downloaded in ipod is $\boxed{\text{pedometer app}+\text{math app}}$ or $\boxed{\text{Photo app}}$ .

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Answer details:

Grade: Junior school

Subject: Mathematics

Chapter: Simplification

Keywords: Combination, simplification, meyer, memory, download, app, photo app, pedometer app, GB, 0.64, 0.24, math app, ipod.

The lesser of two consecutive even integers is 10 more than one-half the greater. Find the integers.

Answers

Hello,

Here's my solution:

Let n = the lesser of the two consecutive even integers; so what will be a good way to represent the greater of the two consecutive even integers? I say n + 2.

Let's write the equation:
n = ((n+2)/2) + 10

I'll multiply both sides of the equation by 2 to eliminate the denominator, getting:
2n = 2[((n+2)/2) + 10]

This reduces to:
2n = n+2 + 20

Which can be further simplified to:
2n = n+22

Subtracting n from both sides we get:
n = 22

So n, the lesser consecutive even integer is 22. The greater consecutive even integer is 24.

Let's check this solution by substituting n = 22 into our original equation:

n = ((n+2)/2) + 10

22 = ((22+2)/2) + 10
22 = ((24)/2) + 10
22 = (12) + 10
22 = 22 - it checks!

An employee works for $45 hours each week. He is paid $4 per hour for 40 hours per week and $6 per hour for overtime, what is his gross weekly wage?