4(2+3c)=56 What would be the answer? Really Need Help On Sovling Multi-Step Equations

Answers

Answer 1
Answer: this should help you, Simplifying 4(2 + 3c) = 56(2 * 4 + 3c * 4) = 56(8 + 12c) = 56Solving8 + 12c = 56Solving for variable 'c'.Move all terms containing c to the left, all other terms to the right.Add '-8' to each side of the equation.8 + -8 + 12c = 56 + -8Combine like terms: 8 + -8 = 00 + 12c = 56 + -812c = 56 + -8Combine like terms: 56 + -8 = 4812c = 48Divide each side by '12'.c = 4Simplifyingc = 4
Answer 2
Answer: 8 + 12C = 56

12C = 48

C = 4

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By how many cm is 1/10 m longer than 1/100 m

Answers

1 cm is 1/100 m
so is 1/10 meter is 9 cm longer than 1/100 meter.

What are the slope, m, and y-intercept, (0, b), of the line described bythe equation 3x + 6y=12?
Write an
anation in
I have no idea how to do this I need help

Answers

Answer:

\large \boxed{m = -(1)/(2);\text{ y-intercept = 2}}}

Step-by-step explanation:

The slope-intercept form of an equation is

y = mx + b, where

m = the slope and

b = the y-intercept

We must solve your equation for y.

It will then be in the slope-intercept form.

\begin{array}{rcll}3x + 6y  & = & 12 & \n6y & = & 12 - 3x & \text{Subtracted 3x from each side}\ny&= &2 -(1)/(2)x& \text{Divided each side by 3}\n\mathbf{y} &= & \mathbf{-(1)/(2)x + 2}& \text{Rearranged terms}\n\end{array}\n\n\large \boxed{\mathbf{m = -(1)/(2);\textbf{y-intercept = 2}}}

The diagram below shows the equation of your graph with m = -½ and the y-intercept at (0, 2)

if 60 seconds are in a minute 60 minutes are in an hour and 24 hours in a day then 86400 seconds are in a day what type of reasoning is this

Answers

Answer:

This is a deductive reasoning.

Step-by-step explanation:

Every statement like 60 seconds are in a minute, and 60 minutes are in a hour, and 24 hours are in a day is a premise. The conclusion is that there are 86,400 seconds in a day, which comes from: 24 hours / day * 60 minutes / hour * 60 second / minute = 86,400 second / day.

MARK ME AS BRAINLIST PLZ I REALLY NEED IT

I need to figure out the answer

Answers

Hello there,

If c=-2 just plug in -2 for every c you see.

(-2)²-7(-2)-8
This simplifies to
4+14-8
18-8
10

Hope this helps!
The answer to the problem is 10 because negative 2 squared is 4 plus 14 because negative 2 times negative 7 is 14 minus 8 which gives you 10. 

Find all possible value of the given variable 1.h²+5h=0
2.z²-z=0
3.m²+13m+40=0
4.z²-3z=0
5.q²+7q=0
6.k²+2k=0
7.x²-3x-70=0
8.q²+7q-60=0
9.z²+9z-36=0
10.d²-13d+22=0

Answers

1.\n \n h^2+5h=0 \n \nh(x+5)=0\n \nx=0 \ \ \ or \ \ \ x+5 =0\ \ |-5\n \nx+5-5=0-5\n \nx=0 \ \ \ or \ \ \ x=-5


2.\n \n z^2-z=0\n \nz(x-1)=0\n \nz=0 \ \ \ or \ \ \ z-1 =0 \ \ | +1\n \nz-1+1 =0 +1 \n \nx=0 \ \ \ or \ \ \ z=1


3.\n \nm^2+13m+40=0 \n \na=1 ,\ b=13, \ c=40 \n \n\Delta =b^2-4ac =13^2-4\cdot 1\cdot 40=169 - 1600=-1431 \n \nand \ we \ know \ when \ \Delta \ is \ negative, \ theres \ no \solution


4.\n \nz^2-3z=0 \n \n (z-3)=0\n \nz=0 \ \ \ or \ \ \ z-3 =0\ \ |+3\n \n z-3+3=0+3\n \nz=0 \ \ \ or \ \ \ z=3


5.\n \nq^2+7q=0 \n \nq(q+7)=0\n \nq=0 \ \ \ or \ \ \ q+7 =0\ \ |-7\n \nq+7-7=0-7\n \nq=0 \ \ \ or \ \ \ q=-7


6.\n \nk^2+2k=0\n \nk(k+2)=0\n \nk=0 \ \ \ or \ \ \ k+2 =0\ \ |-2\n \nk+2-2=0-2\n \nk=0 \ \ \ or \ \ \ k=-2


7. \n \n x^2-3x-70=0 \n \na=1,\ b=-3, \ c=-70 \n \n\Delta =b^2-4ac = (-3)^2-4\cdot 1\cdot (-70)= 9+280=289\n \n x_(1)=(-b-√(\Delta) )/(2a)=(3-√(289))/(2 )=( 3-17)/(2)=(-14)/(2)=-7

x_(2)=(-b+√(\Delta) )/(2a)=(3+√(289))/(2 )=( 3+17)/(2)=(20)/(2)=10\n \n(x+7)(x-10)=0


8.\n \nq^2+7q-60=0 \n \na=1,\ b=7, \ q=-60 \n \n\Delta =b^2-4ac = 7^2-4\cdot 1\cdot (-60)=49+240=289 \n \n x_(1)=(-b-√(\Delta) )/(2a)=(-7-√(289))/(2 )=( -7-17)/(2)=(-24)/(2)=-12

x_(2)=(-b+√(\Delta) )/(2a)=(-7+√(289))/(2 )=( -7+17)/(2)=( 10)/(2)= 5\n \n(x+12)(x-5)=0


9.\n \nz^2+9z-36=0 \n \na=1,\ b=9, \ q=-36 \n \n\Delta =b^2-4ac = 9^2-4\cdot 1\cdot (-36)= 81+144=225\n \n x_(1)=(-b-√(\Delta) )/(2a)=(-9-√(225))/(2 )=( -9-15)/(2)=(-24)/(2)=-12

x_(2)=(-b+√(\Delta) )/(2a)=(-9+√(225))/(2 )=( -9+15)/(2)=(6)/(2)=3\n \n(x+11)(x-3)=0


10.\n \nd^2-13d+22=0 \n \na=1,\ b=-13, \ q=22 \n \n\Delta =b^2-4ac = (-13)^2-4\cdot 1\cdot 22= 169-88=81\n \n d_(1)=(-b-√(\Delta) )/(2a)=(13-√(81))/(2 )=( 13-9)/(2)=(4)/(2)=2

d_(2)=(-b+√(\Delta) )/(2a)=(13+√(81))/(2 )=( 13+9)/(2)=(22)/(2)=11\n \n(d-2)(d-11)=0


I don't understand can someone help please

Answers

In a whole hour, a half-hour goes by, two times.

In the first half-hour, 7/8 of a gallon leaks out of the pool.
In the second half-hour, another 7/8 of a gallon leaks out of the pool.

In the whole hour,  (7/8 gallon + 7/8 gallon) leaks from the pool.

Can you add those two fractions, and make a single number ?
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