How do I solve this problem? 6m+3(2m+5)+7

Answers

Answer 1
Answer:

The final expression will be 12m + 22 .

Given,

6m+3(2m+5)+7

Here,

6m+3(2m+5)+7

To solve the above expression firstly open the brackets by multiplying 3 inside the  bracket  .

So,

6m + 6m + 15 + 7

Now add the the terms having similar variables ,

So,

6m and 3m will be added,

= 12m

Now add the constant terms,

15 + 7 = 22

Thus the final expression will be ,

12m + 22

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Answer 2
Answer: 1. Combine like terms. So, combine the numbers with a variable. Then the numbers without variables. (Also known as simplifying the expression)

6m+3(2m+5)+7
12m+22

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Which expression finds the measure of an angle that is coterminal with a 126° angle?A. 126° + (275n)°, for any integer n
B. 126° + (375n)°, for any integer n
C. 126° + (450n)°, for any integer n
D. 126° + (720n)°, for any integer n

Answers

The expression that gives an angle that is coterminal with 126 is 126 + 720n. Two angles are said to be coterminal if when they are drawn in a standard position, their terminal sides are on the same location. The expression will give an angle which when it is drawn the terminal sides are on the same location with the 126 angle.

The option (D) 126° + (720n)°, for any integer n is correct for any integer n.

What is coterminal angles?

Two different angles that have the identical starting and ending edges termed coterminal angles however, since one angle measured clockwise and the other determined counterclockwise, the angles' terminal sides have completed distinct entire rotations.

We have an angle of 126 degree

As we know from the definition of the coterminal angle.

If any angle θ the coterminal angles are:

= θ + 360n  (for any integer n)

Plug n = 2n

= θ + 720n  (for any integer n)

Also represents the coterminal angle.

Thus, the option (D) 126° + (720n)°, for any integer n is correct for any integer n.

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Answers

debt means negative ballance

greater than 20 and less than 30
means owes more than -20 and less than -30
-20>x>-30

-24 is answer

The area of a rectangular painting is 4275cm². if the length of the painting is 75cm, what is its width?

Answers

Answer:

Width = 57cm

Step-by-step explanation:

The area of a rectangle can be found by using the formula:

Area = Length * Width

Since we know that the area is 4275cm² and the length of the painting is 75cm, we can plug these into the above equation to solve for the width.

Area = Length * Width

4275cm² = 75cm * Width

To find the width, we can simply divide both sides by 75 so that the width measurement is isolated:

Width = 57cm

To verify this, we can multiply the length and width to see if the area equals 4275cm²:

75cm * 57cm = 4275cm²

Convert -2.36 to a fraction in lowest terms

Answers

Answer:

59/25 I believe

:)

Step-by-step explanation:

franko pays ​$48.75 for fifteen 14​-count boxes of granola bars. How much does 1 box of granola bars​ cost

Answers

Answer: 3.25

Step-by-step explanation: To calculate the price of a single box of granola bars we take the total price and divide it by 15 (the amount of boxes purchased) to get $3.25 per box of 14-count granola bars.

Awaste management company is designing a rectangular construction dumpster that will be twice as long as it is wide and must hold 19y * d ^ 3 of debris. Find the dimensions of the dumpster that will minimize its surface area.

Answers

Answer:

1.92 yd  x 3.83 yd  x 2.58 yd

Step-by-step explanation:

We have given a rectangular base, that its twice as long as it is wide.

It must hold 19 yd³ of debris.

Lets minimize the surface area, subject to the restriction of volume (19 yd³)

The surface is given by:

S=2(w*h+w*2w+2wh)=2(3wh+2w^2)

The volume restriction is:

V=w*2w*h=2w^2h=19\n\nh=(9.5)/(w^2)

replacing h in the surface equation, we have:

S=2(3wh+2w^2)=6w((9.5)/(w^2))+4w^2=57w^(-1)+4w^2

Derivate the above equation and set it to zero

dS/dw=57(-1)w^(-2) + 8w=0\n\n57w^(-2)=8w\n\nw^3=57/8=7.125\n\nw=\sqrt[3]{7.124} =1.92

The height will be:

h=9.5/w^2=9.5/(1.92^2)=9.5/2.69=2.58

Therefore,The dimensions that minimize the surface are:

Wide: 1.92 yd  

Long: 3.83 yd

Height: 2.58 yd