The final expression will be 12m + 22 .
Given,
6m+3(2m+5)+7
Here,
6m+3(2m+5)+7
To solve the above expression firstly open the brackets by multiplying 3 inside the bracket .
So,
6m + 6m + 15 + 7
Now add the the terms having similar variables ,
So,
6m and 3m will be added,
= 12m
Now add the constant terms,
15 + 7 = 22
Thus the final expression will be ,
12m + 22
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B. 126° + (375n)°, for any integer n
C. 126° + (450n)°, for any integer n
D. 126° + (720n)°, for any integer n
The option (D) 126° + (720n)°, for any integer n is correct for any integer n.
Two different angles that have the identical starting and ending edges termed coterminal angles however, since one angle measured clockwise and the other determined counterclockwise, the angles' terminal sides have completed distinct entire rotations.
We have an angle of 126 degree
As we know from the definition of the coterminal angle.
If any angle θ the coterminal angles are:
= θ + 360n (for any integer n)
Plug n = 2n
= θ + 720n (for any integer n)
Also represents the coterminal angle.
Thus, the option (D) 126° + (720n)°, for any integer n is correct for any integer n.
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Answer:
Width = 57cm
Step-by-step explanation:
The area of a rectangle can be found by using the formula:
Area = Length * Width
Since we know that the area is 4275cm² and the length of the painting is 75cm, we can plug these into the above equation to solve for the width.
Area = Length * Width
4275cm² = 75cm * Width
To find the width, we can simply divide both sides by 75 so that the width measurement is isolated:
Width = 57cm
To verify this, we can multiply the length and width to see if the area equals 4275cm²:
75cm * 57cm = 4275cm²
Answer:
59/25 I believe
:)
Step-by-step explanation:
Answer: 3.25
Step-by-step explanation: To calculate the price of a single box of granola bars we take the total price and divide it by 15 (the amount of boxes purchased) to get $3.25 per box of 14-count granola bars.
Answer:
1.92 yd x 3.83 yd x 2.58 yd
Step-by-step explanation:
We have given a rectangular base, that its twice as long as it is wide.
It must hold 19 yd³ of debris.
Lets minimize the surface area, subject to the restriction of volume (19 yd³)
The surface is given by:
The volume restriction is:
replacing h in the surface equation, we have:
Derivate the above equation and set it to zero
The height will be:
Therefore,The dimensions that minimize the surface are:
Wide: 1.92 yd
Long: 3.83 yd
Height: 2.58 yd