B.) general relativity
C.) law of conservation of momentum
D.) thermodynamics
The object be going at the bottom of the hill with velocity 7.75 m/s.
When an item is moving, its velocity is the rate at which its direction is changing as seen from a certain point of view and as measured by a specific unit of time.
Given in the question a 400 kg object is sitting at rest at the top of a hill that is 30.0 m high and 80.0 m long measured along the hill . If there is no friction, velocity with which object be going at the bottom of the hill,
θ =sin^-1(30/80)
θ =22
F = 400 g sin(22) = 150 N
F = ma
150 = 400 a
a = 0.375 m/s²
v² - u²= 2 a s
v² - 0 = 2 x 0.375 x 80
v = 7.75 m/s
The object be going at the bottom of the hill with velocity 7.75 m/s.
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2. Calculate the pressure in atmospheres using the van der Waals equation. For N2 , a=1.35 (L2⋅atm)/mol2 , and b=0.0387 L/mol
Answer:
1) 16.88 atm
2) 34.47 atm
Explanation:
Data:
Volume=0.700L
Temperature = 300K
Number of moles=0.480 mol
Ideal gas constant=0.082057 L*atm/K·mol
1) The ideal gas law is:
(1)
with P the pressure, T the temperature, n the number of moles, V the volume and R the ideal gas constant , so solvig (1) for P:
2) The vander Walls equation is:
solving for P
The pressure in atmospheres is 0.974 atm using the ideal gas law and 0.962 atm using the van der Waals equation for N2.
1. To calculate the pressure in atmosphere using the ideal gas law, we can use the equation PV = nRT, where P is pressure, V is volume, n is the number of moles, R is the ideal gas constant (0.0821 L·atm/mol·K), and T is the temperature in Kelvin.
Rearranging the equation, we have P = (nRT)/V. Plugging in the given values, we get P = (0.480 mol * 0.0821 L·atm/mol·K * 300 K) / 0.700 L = 0.974 atm.
2. To calculate the pressure in atmosphere using the van der Waals equation, we can use the equation (P + an^2/V^2)(V - nb) = nRT, where a and b are constants specific to the gas being used. Rearranging the equation, we have P = (nRT/(V - nb)) - an^2/V^2.
Plugging in the given values and the constants for N2, we get P = (0.480 mol * 0.0821 L·atm/mol·K * 300 K/(0.700 L - 0.0387 L/mol * 0.480 mol))^2 - 1.35 (L^2·atm)/mol^2 * (0.480 mol)^2/(0.700 L)^2 = 0.962 atm.
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(b) what's the maximum acceleration of the needle ?
Answer:
The tip of the needle to move from the highest point to the lowest point in 0.4 sec and the needle tip to travel a total distance in 0.9 sec.
Explanation:
Given that,
Frequency = 2.5 Hz
Amplitude = 1.27 cm
(a). We need to calculate the time
The frequency is the reciprocal of the time.
The time taken from highest point to lowest point
(b). We need to calculate the time
The time taken in one cycle = 0.4 sec
The distance covered in one sec= 4 times x amplitude
We need to calculate the speed
Using formula of speed
We need to calculate the time
Hence, The tip of the needle to move from the highest point to the lowest point in 0.4 sec and the needle tip to travel a total distance in 0.9 sec.
c. has strong, spinning winds
b. has warm, calm air and light winds
d. has spiraling bands of heavy rain
Answer:
Explanation:
The eye of a hurricane is calm and "peaceful", it's the region with calm weather. But the eyewall is really dangerous, due to its pressure and speed difference. Actually, the eyewall has the most severe winds and weather. Another important characteristic is that the eye has the lower pressure.
So, among the options, b. is the right answer.
b. has warm, calm air and light winds
Answer: Is the movement of sediment by gravity.
Mass wasting is the movement of sediments generate due to the mass movement of rock, soil or other debris from a hilly or slopy region downwards due to the effect of gravity. This effect can be highly be observed during landslides. Agents like wind and water also promote this effect.
Mass wasting is the movement of sediment by gravity transports. Meaning the earth’s outer crust is being ‘wasted’ away on a ‘massive’ scale and falling to lower elevations. It is also a type of erosion and can make changes to the side of the mountain.