What is the slope of the line that passes through the points (-1,4) and (-6,-2) ?

Answers

Answer 1

Answer: I showed you the formula in the other question, y2-y1/x2-x1 = slope. So the answer is -6/7

Answer 2

Answer: so the formula is m=y2-y1/x2-x1
Therefore substitute
so, m=-2-4/-6-(-1)
therefore, m = -6/-5
so, m= 6/5
then write a sentence answer if necessary

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H(t) = -5t^2+20t+1 what time does the ball reach the same height it was kicked at again? When does the ball reach its max height? What is the max height?

Answers

h(t) = -5t² + 20t + 1
-5t² + 20t + 1 = 0
t = -(20) +/- √((20)² - 4(-5)(1))
      2(-5)
t = -20 +/- √(400 + 20)
      -10
t = -20 +/- √(420)
-10
t = -20 +/- 2√(105)
-10
t = -20 + 2√(105) t = -20 - 2√(105)
   -10    -10
t = 2 - 0.2√(105) t = 2 + 0.2√(105)
h(t) = -5t² + 20t + 1
h(2 - 0.2√(105)) = -5(2 - 0.2√(105))² + 20(2 - 0.2√(105)) + 1
h(2 - 0.2√(105)) = -5(2 - 0.2√(105))(2 - 0.2√(105)) + 20(2) - 20(0.2√(105)) + 1
h(2 - 0.2√(105)) = -5(4 - 0.4√(105) - 0.4√(105) + 0.04√(11025)) + 40 - 4√(105) + 1
h(2 - 0.2√(105)) = -5(4 - 0.8√(105) + 0.04(105)) + 40 + 1 - 4√(105)
h(2 - 0.2√(105)) = -5(4 - 0.8√(105) + 4.2) + 41 - 4√(105)
h(2 - 0.2√(105)) = -5(4 + 4.2 - 0.8√(105)) + 41 - 4√(105)
h(2 - 0.2√(105)) = -5(8.2 - 0.8√(105)) + 41 - 4√(105)
h(2 - 0.2√(105)) = -5(8.2) - 5(-0.8√(105)) + 41 - 4√(105)
h(2 - 0.2√(105)) = -41 + 4√(105) + 41 - 4√(105)
h(2 - 0.2√(105)) = -41 + 41 + 4√(105) - 4√(105)
h(2 - 0.2√(105)) = 0 + 0
h(2 - 0.2√(105)) = 0
(t, h(t)) = (2 - 0.2√(105), 0)
or
h(t) = -5t² + 20t + 1
h(2 + 0.2√(105)) = -5(2 + 0.2√(105))² + 20(2 + 0.2√(105)) + 1
h(2 + 0.2√(105)) = -5(2 + 0.2√(105))(2 + 0.2√(105)) + 20(2) + 20(0.2√(105)) + 1
h(2 + 0.2√(105)) = -5(4 + 0.4√(105) + 0.4√(105) + 0.04√(11025)) + 40 + 4√(105) + 1
h(2 + 0.2√(105)) = -5(4 + 0.8√(105) + 0.04(105)) + 40 + 4√(105) + 1
h(2 + 0.2√(105)) = -5(4 + 0.8√(105) + 4.2) + 40 + 1 + 4√(105)
h(2 + 0.2√(105)) = -5(4 + 4.2 + 0.8√(105)) + 41 + 4√(105)
h(2 + 0.2√(105)) = -5(8.2 + 0.8√(105)) + 41 + 4√(105)
h(2 + 0.2√(105)) = -5(8.2) - 5(0.8√(105)) + 41 + 4√(105)
h(2 + 0.2√(105)) = -41 - 4√(105) + 41 + 4√(105)
h(2 + 0.2√(105)) = -41 + 41 - 4√(105) + 4√(105)
h(2 + 0.2√(105)) = 0 + 0
h(2 + 0.2√(105)) = 0
(t, h(t)) = (2 + 0.2√(105), 0)

i am a three digit number. i am divisible by 5. i am an even number each of my digits are different my tens is greater than my ones digit. my hundreds digit is greater than my tens digit. i am less than 400. i am divisible by 3. i have only one odd digit. my tens digit is 1. what number am i?

Answers

Answer:

210

I am divisible by 5.

So your ones digit is 0 or 5

I am an even number.

So your ones digit is 0. We fill that in.

_ _ 0

My tens digit is 1.

So we fill that in.

_ 1 0

My tens digit is greater than my ones digit.

Well, of course 1 is greater than 0. We didn't need to be told that.

I have only one odd digit.

Since the 1 is odd, the hundreds digit is even, 2,4, or 8

I am less than 400.

So your hundreds digit is 2. Fill that in and we're done.

2 1 0

My hundreds digit is greater than my tens digit.

Of course 2 is greater than 1, we didn't need to be told that.

I am divisible by 3.

Of course 210 is divisible by 3. We didn't need to be told that.

Too much information!

Answer: 210

You are choosing between two health clubs. Club A offers membership for a fee of $ 14 $14 plus a monthly fee of $ 15. $15. Club B offers membership for a fee of $ 18 $18 plus a monthly fee of $ 14. $14. After how many months will the total cost of each health club be the same? What will be the total cost for each club?

Answers

Answer:

After 4 months total cost of each health club would be the same that is $74.

Step-by-step explanation:

Let x represent number of months.

We have been given that Club A offers membership for a fee of $14 plus a monthly fee of $15.

The total cost of using Club A for x months would be $15x+14$ .

We have been given that Club B offers membership for a fee of $18 plus a monthly fee of $14.

The total cost of using Club B for x months would be $14x+18$ .

Let us equate both equations to find number of months, when both health clubs cost would be same.

$15x+14=14x+18$

$15x-14x+14=14x-14x+18$

$x+14=18$

$x+14-14=18-14$

$x=4$

Therefore, after 4 months the total cost of each health club would be the same.

The total cost of using Club A: $15(4)+14=60+14=74$

The total cost of using Club B: $14(4)+18=56+18=74$

Therefore, the total cost for each club would be $74.

What is x?
3(x - 4) - 14 = 2(x - 7) + 6

Answers

$3(x - 4) - 14 = 2(x - 7) + 6 \n \n 3x - 12 - 14 = 2x - 14 + 6 \ / \ expand \n \n 3x - 26 = 2x - 14 + 6 \ / \ simplify \n \n 3x - 26 = 2x - 8 \ / \ simplify \n \n 3x = 2x - 8 + 26 \ / \ add \ 26 \ to \ each \ side \n \n 3x = 2x + 18 \ / \ simplify \n \n 3x - 2x = 18 \ / \ subtract \ 2x \ from \ each \ side \n \n x = 18 \ / \ simplify \n \n$

The final result is x = 18.

3(x - 4) - 14 = 2(x - 7) + 6
⇒ 3x+ 3(-4) -14= 2x+ 2*7+ 6 (distributive property)
⇒ 3x -12 -14= 2x -14+ 6
⇒ 3x+ (-12 -14)= 2x+ (-14+ 6) (combine like terms)
⇒ 3x -26= 2x -8
⇒ 3x -2x= -8+ 26 (inverse operation)
⇒ x= 18

Final answer: x= 18.

Solve using the addition and multiplication principles. 8x-6<=34

Answers

Answer: x ≤ 5

Step-by-step explanation:

Our task is to solve the following inequality:

$\sf{8x-6\leq34}$

Remember that in every equation and inequality, we need to isolate x. To isolate x, we need to follow these steps:

add 6 to each side
divide each side by 8

--------------

step one

--------------

Add 6 to both sides:

$\sf{8x\leq40}$

--------------

step two

--------------

Divide both sides by 8:

$\sf{x\leq5}$ {answer}. You're done! ^^'

Final answer:

To solve the inequality 8x - 6 <= 34 using the addition and multiplication principles, follow these steps: add 6 to both sides, then divide both sides by 8. The solution is x <= 5.