1,060,060 in expanded form

Answers

Answer 1

Answer: The correct way to write $1, 060, 060$ in expanded form is:

1, 000, 000 + 60, 000 + 60...

Hope this helped :)

Answer 2

Answer: 1,00,000+60,000+60 in expanded form

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Regina wanted an increase in her weekly allowance from $5 to $10, but her parents did her one better. Instead, Regina rolls a fair, six-side die every week, and her allownace for that week will be the number she rolls multiplied by 2. Write and expression where n represents the number on the die that Regina rolls that week.

Answers

The expression is 2n

28. What is the maximum number of real rootsthe equation X5 - 3x3 + 8x – 10 can have? Justify
your answer.

Answers

The maximum number of real roots is 5 because the degree is 5. The fundamental theorem of algebra states that the degree of a polynomial is the number of real solutions. (The degree is the highest exponent of the polynomial)

How to set up 701 km -523 km 445 m

Answers

answer: 177.555km
convert 445m into 0.445km
and so it's 701-523.445=177.555km

Convert - 445m into 0.445km
So it's 701-523.445 = 177.555km

Hope I Helped!!! :-)

Have A Good Day!!!

50 POINTS! Vectors u, v, and w are shown in the graph. What are the magnitude and direction of u + v + w? Round the magnitude to the thousandths place and the direction to the nearest degree.

Answers

Answer:

C) 48.786, 152°

Step-by-step explanation:

To add the vectors u, v and w, we first need to rewrite each vector in component form (where vectors are represented using the unit vectors i and j along the x and y axes).

The (x, y) components of a vector, given its magnitude (r) and direction (θ), are (r cos θ, r sin θ), where θ is measured in the anticlockwise direction from the positive x-axis.

Every vector in two dimensions is made up of horizontal and vertical components, so any vector can be expressed as a sum of i and j unit vectors. Therefore, the i + y form of a vector is:

(r cos θ) i + (r sin θ) j

So, the component form of the given vectors are:

$\mathbf{u}=80 \cos 230^(\circ)\textbf{i}+80 \sin 230^\circ}\textbf{j}$

$\mathbf{v}=60 \cos 120^(\circ)\textbf{i}+60 \sin 120^\circ}\textbf{j}$

$\mathbf{w}=50 \cos 40^(\circ)\textbf{i}+50 \sin 40^\circ}\textbf{j}$

Sum the vectors:

$\mathbf{R}=\mathbf{u}+\mathbf{v}+\mathbf{w}\n\n\mathbf{R}=(80 \cos 230^(\circ)+60 \cos 120^(\circ)+50 \cos 40^(\circ))\textbf{i}+(80 \sin 230^\circ}+60 \sin 120^\circ}+50 \sin 40^\circ})\:\textbf{j}\n\n\mathbf{R}=-43.1207866\:\textbf{i}+22.8173493\:\textbf{j}$

$\textsf{For a vector\;\;$\mathbf{a} = x\mathbf{i} + y\mathbf{j}$, its magnitude is\;\;$||\mathbf{a}|| = √(x^2+y^2)$.}$

Calculate the magnitude of the resultant vector ||R||:

$\mathbf{||R||}=√((-43.1207866)^2+(22.8173493)^2)\n\n\mathbf{||R||}=48.7855887...\n\n\mathbf{||R||}=48.786$

The direction θ can be found by finding the angle with the horizontal, which is given by:

$\boxed{\theta=\tan^(-1)\left((y)/(x)\right)}$

As the resultant vector is in quadrant II (since the i component is negative and the j component is positive), we need to add 180° to the value of tan⁻¹(y/x). Therefore:

$\theta=\tan^(-1)\left((22.8173493)/(-43.1207866)\right)+180^(\circ)$

$\theta=-27.8855396+180^(\circ)$

$\theta=152.114460^(\circ)$

$\theta=152^(\circ)\; \sf (nearest\;degree)$

Therefore:

Magnitude = 48.786
Direction = 152°

The answer is c :48.786; 152°

Explain how showing fractions with models and a number line are alike and different

Answers

In order to find the distance between -61.5 and -23.4 on the number line, you just have to subtract either the greater value to lesser value or lesser value to the greater value. It doesn't matter when you get a negative difference because the distance should be the absolute value of the difference of two points on a number line.
Here's how you should do it.
(-61.5) - (-23.4) = -61.5 + 23.4 = l-38.1l = 38.1
or
(-23.4) - (-61.5) = -23.4 + 61.5 = l38.1l = 38.1

As you can see above, I tried to subtract the two numbers in different order, and the result is still the same. Just make sure to get the absolute value of the answer because the distance should always be in positive form.

Therefore, the distance between -61.5 and -23.4 is 38.1

Martin chose two of the cards below. When he found the quotient of the numbers, his answer was -16/9. Write the division problem that Martin solved