B) Which container should be used to fit a dozen film containers with the least amount of wasted space? Explain your reasoning.
At work you get a list of package sizes. Your store has four box sizes that look like they might work. The sizes are given in the form l x w x h. They are 3 in. x 2 in. x 5 in., 4 in. x 3in. x 2 in., 5 in. x 6 in. x 5 in., and 3 in. x 2 in. x 3 in.
Answer:
(a)18.85 Cubic Inches
(b)The box with dimensions of 4 in. x 3in. x 2 in.
Step-by-step explanation:
Part A
Volume of the 12 Containers
Height =2 Inches
Diameter=1 Inch
Radius=Diameter/2=1/2=0.5 Inch
Volume of a cylinder
Volume of the 12 Containers
Part B
To determine the container which should be used, we first determine the volume of the available boxes.
Volume of the boxes
Volume of box with dimension 3 in. x 2 in. x 5 in.=3X2X5=30 Cubic Inches
Volume of box with dimension 4 in. x 3in. x 2 in.=4X3X2=24 Cubic Inches
Volume of box with dimension 5 in. x 6 in. x 5 in.=5X6X5=150 Cubic Inches
Volume of box with dimension 3 in. x 2 in. x 3 in. =3X2X3=18 Cubic Inches
The box that should be used with the least amount of wasted space is he box with volume 24 Cubic inches. i.e. box with dimensions 4 in. x 3in. x 2 in.
This is because the volume of the box(18 cubic inches) with dimension 3 in. x 2 in. x 3 in. is less than what is required.
Please help!! Answer correctly and no guessing, please!
The first thing you must do is find KL. You use a^2 + b^2 = c^2 to do that.
Then you find the various sines and cosines and Tangents of the angles involved.
Step One
Find KL
a^2 + b^2 = c^2
c = 219
b = 178
a = ??
219^2 = 178^2 + a^2
47061 = 31684 + a^2
a^2 = 48061 - 31684
a^2 = 127.97
Step Two.
Find the sines and cosines of J and L
Choice A
Sin(J) =opposite/hypotenuse = 127/219 = 0.5799
Cos(L) = adjacent/hypotenuse = 127/219 = 0.5799
Conclusion Sin(J) = Cos(L) A is not true. Neither is bigger than the other.
Choice B
Choice B does exactly what Choice A did. The Sin of L is the same thing as the cos(J).
Choice C
C can't be true.
Tan(J) = opposite / Adjacent. = 127/178
Tan(L) = opposite / Adjacent = 178/127
One is larger than 1 and the other one is less than 1. They use the same values but in a different order.
D
We discussed this for choice A. So D is the correct answer
First you need to find out what K and L's angle is
Step #1: Finding L's angle number
to do this you are going to subtract 219-178=?
answer should be 41.
Step #2: Desiding if J is Larger than L
Is 219 Larger than 41? or is 41 larger than 219?
b) 9x = 6x + 12
c) 5x - 1 = 3x + 11
d) 2x + 8 = x + 13
5. Um retangulo com 100 cm de perímetro apresenta a medida do lado maior com 10 cm a mais que o lado menor. Quanto mede o lado menor dessa figura geométrica?
Answer:
4. a)
5. shorter side of the rectangle measures 20 cm.
Step-by-step explanation:
Answer:
A
Step-by-step explanation:
1/4 of 1/4
= 1/8
13 x 1/8
= 13/1 x 1/8
= 1 5/8
therefore there are 1 and 5/8 in the line of rickys fraction strips.
on a fraction strip line this is 13/8