y= (x+6)(x+2)(x+8)/(x+9)(x+7)
Answer:
You spent 40% of your budget on office supplies.
Step-by-step explanation:
1. First take the total budget:
$25
2. Then take the money you spent on office supplies and divide it by the total budget to find the ratio you spent:
3. Finally multiply the ratio by a hundred to find the percentage of the budget you spent on office supplies:
%
Therefore, you spent 40% of your budget on office supplies.
Unitconversion is the conversion of one unit to another unit with its standardconversion.
1 ml = 0.001 L
1 ml = 0.01 dL
1 dkL = 10,000 ml
13.6 ml = 0.0136 L
13.6 ml = 0.136 dL
13.6 ml = 0.00136 dkL
Options A and B are the correct answer.
It is the conversion of one unit to another unit with its standardconversion.
Example:
1 minute = 60 seconds
1 km = 1000 m
We have,
13.6 milliliters.
1 ml = 0.001 L
1 ml = 0.01 dL
1 dkL = 10,000 ml
Now,
1 ml = 0.001 L
13.6 ml = 13.6 x 0.001 L
13.6 ml = 0.0136 L
1 ml = 0.01 dL
13.6 ml = 13.6 x 0.01 dL
13.6 ml = 0.136 dL
10,000 ml = 1 dkL
1 ml = 0.0001 dkL
13.6 ml = 13.6 x 0.0001 dkL
13.6 ml = 0.00136 dkL
Thus,
13.6 ml = 0.0136 L
13.6 ml = 0.136 dL
13.6 ml = 0.00136 dkL
Options A and B are the correct answer.
Learn more about unitconversion here:
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The correct answer is 0.0136 dkl. hope it helps uwu
Answer:
the square root of 16 is 4
Step-by-step explanation:
–12p2– 12pq + 2p – 3q2 + q
–9p2q2 + 12pq – 2p + q
12p2 + 12pq +2p + 3q2 + q
The product of the 2p + q and –3q – 6p + 1 is .
Given
The given terms are;
2p + q and –3q – 6p + 1
To find a product, you'll need to multiply at least two numbers together following all the steps given below.
The product of the terms is;
Hence, the product of the 2p + q and –3q – 6p + 1 is .
To know more about Product click the link given below.
Answer: Second option is correct.
Step-by-step explanation:
Since we have given that
We need to product the two polynomials .
Here it is :
Hence, Second option is correct.
Answer:
Distributive Propety
Step-by-step explanation:
We are given the following information in the question:
Distributive Property:
The given problem can be solved as: