What is the answer to this math problem 40+40x0+1=

Answers

Answer 1
Answer: using pemdas
we multiple 40*0=0
40+0+1
=41
Answer 2
Answer:

Answer:

40+40*0+1=

40*0=0

0+40+1=

41


Related Questions

Use the properties of operations to multiply the expressions. (t + t)(4.9t)
If x + 3 is a multiple of 3, which of thefollowing is not a multiple of 3? (A) x (B) x + 6 (C) 6x + 18 (D) 2x + 6 (E) 3x + 5
Divide 12 x²y²z by 6xyz​
What is the greatest common factor of 8m, 36m3, and 12? 4 8 4m 8m
Ou have learned that given a sample of size n from a normal distribution, the CL=95% confidence interval for the mean can be calculated by Sample mean +/- z((1-CL)/2)*Sample std/sqrt(n). Where z((1-cl)/2)=z(.025) is the z score.a. help(qnorm) function. Use qnorm(1-.025) to find z(.025).b. Create a vector x by generating n=50 numbers from N(mean=30,sd=2) distribution. Calculate the confidence interval from this data using the CI formula. Check whether the interval covers the true mean=30 or not.c. Repeat the above experiments for 200 times to obtain 200 such intervals. Calculate the percentage of intervals that cover the true mean=30. This is the empirical coverage probability. In theory, it should be very close to your CL.d. Write a function using CL as an input argument, and the percentage calculated from question c as an output. Use this function to create a 5 by 2 matrix with one column showing the theoretical CL and the other showing the empirical coverage probability, for CL=.8, .85, .9, .95,.99.

Which property is illustrated by the equation (a+b)+c=c+(a+b)

Answers

Associative property of addition Which property is illustrated by the equation (a+b)+c=c+(a+b) is the associative property of addition. The associative property of addition groups addends together which still yields the same sum regardless of the clustering or grouping set.
For example:
1.          
1 + (2 + 3) = 6 = (1 + 2) + 3

2.           1 + (2 + 7) = 10 = (1 + 2) + 7
3.           550 + (20 + 5) = 575 = (550 + 5) + 20  



Association Property

Jordan takes 50% of the cherries from a bowl. then Mei takes 50%of the remaining cherries. Finally Greg takes 50 %of the remaining cherries. There are 3 cherries left. How many cherries were in the bowl before Jordan arrived

Answers

Answer:

24

Step-by-step explanation:

Let total cherries in a bowl=x

Jordan takes cherries=50% of x=(50)/(100)x

Remaining cherries=x-(50)/(100)x=(50)/(100)x=(x)/(2)

Mei takes cherries=50% of (50x)/(100)=(x)/(4)

Now, remaining cherries=(x)/(2)-(x)/(4)=(x)/(4)

Greg takes cherries=50% of(x)/(4)=(x)/(8)

Now, remaining cherries=(x)/(4)-(x)/(8)=(x)/(8)

Now,remaining cherries in a bowl=3

We have to find total cherries in a bowl before Jordan arrived.

According to question

(x)/(8)=3

x=3* 8=24

Hence,  total cherries in a  bowl=24

So in the final smallest bowl when half are removed there are 3 so the total amount was double 3 which is 6 before greg removed some.
Mei had removed half of the cherries which left 6 cherries so the total amount before Mei removed half was 12.
Jordan took half of the cherries which left 12. If you follow the same logic you double 12 which makes....
Good luck, hope this helped you understand the question more, feel free to comment and ask for help :)

What is the surface area of the square pyramid below?A square pyramid. The square base has side lengths of 6 centimeters. The triangular sides have a height of 10 centimeters.
120 cm2
132 cm2
156 cm2
276 cm2

Answers

Since the squarebase has side 6 cm and triangular side has height 10 cm, the total surface area of square pyramid is 156 cm²

What is the Total surface area of a square pyramid?

A square pyramid has a square base and four triangular sides, its surface area, A = area of square base + 4 × Area of triangular side.

Area of square base

Area of square with side, L is A = L²

Area of triangularbase

Area of triangle with height and base, L which is the length of the square base is A' = 1/2Lh

Thus, total surface area of square pyramid ,

A" = L² + 4 × 1/2Lh

= L² + 2Lh

Given that the length of the square base is 6 cm and the height of the triangular side is 10 cm.

Now substituting the values of the variables intot he equation, we have

A" = L² + 2Lh

A" = (6 cm)² + 2 × 6 cm × 10 cm

A" = 36 cm² + 120 cm²

A" = 156 cm²

So, the total surface area of square pyramid is 156  cm²

Learn more about total surface area of squarepyramid here:

brainly.com/question/22744289

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Answer:

C) 156cm²

Step-by-step explanation:

1. 6x6=36

2. 6x10=60

3. 60/2=30

4. 30x4=120

5. 120+36=156cm²

Vong grilled 21 burgers at a block party. He grilled the same number of pounds of turkey burgers as hamburgers. Each turkey burger weighed 1/4 & each hamburger weighed 1/3 pound. How many of each did Vong grill?

Answers

x-number\ of\ hamburgers\n21-x-number\ of\ turkey\ burgers\n\n(1)/(4)x=(1)/(3)(21-x)\n\n(1)/(4)x=7-(1)/(3)x\n\n(3)/(12)x+(4)/(12)x=7\n\n(7)/(12)x=7\ \ \ \ \ |\cdot(12)/(7)\n\nx=12\n\n21-12=9\n\nVong\ grilled\ 12\ hamburgers\ and\ 9\ turkey\ burgers

What is 3ft to 7 yd as a fraction in simplest form

Answers

3/7 or three sevenths

Rathan thinks all factors of even numbers are even. Which explains whether Rathan is correct? He is correct because the product of 2 and any number is even.
He is correct because the product of two even numbers is even.
He is incorrect because the product of an even number and an odd number is even.
He is incorrect because the product of two odd numbers is odd

Answers

The answer to this would be C, the third of the options. This is the only response that fully answers the question. For example, two factors of 42 would be 6 and 7, and both are not even, so given the absolute nature of Rathan's belief, there is no exception that can be made to make him correct. I hope this helps, and if it was sufficient to make you understand fully set it to the brainliest answer. Have a nice day! =)

The correct answer is:

He is incorrect because the product of an even number and an odd number is even.  

Explanation:

When you multiply any number by an even number, whether it is even or odd, the product will be even.

This means that an even number can have an odd factor, and Rathan is incorrect.