Answer:
reproducible
Explanation: edg
Answer:
d.] duration
Explanation:
no explanation
K = 9.00 × 109 N ×
r = 3.0 m, determine F.
_____ N
The force is obtained from the charges Q₁ = 3×10⁻⁵ C and Q₂ = 4×10⁻⁵ C and distance r = 3 m is 1.2 N.
Coloumb's law is defined as the force of attraction and repulsion between two charges is directly proportional to the product of charges and inversely proportional to the square of the distance between them.
The attractive and repulsive force, F∝ (q₁×q₂) / r². It is also known as F = k (q₁×q₂) / r², where k is the proportional constant. The unit of force is newton N.
From the given,
Q₁ = 3×10⁻⁵ C
Q₂ = 4×10⁻⁵ C
r = 3m
k = 9×10⁹ Nm²C⁻²
The attractive and repulsive force,
F = k (q₁×q₂) / r²
= (9×10⁹× 3×10⁻⁵×4×10⁻⁵) / (3)²
= 12×10⁻¹
= 1.2 N
Force = 1.2 N
Thus, the force of repulsion and attraction of given charges is 1.2 N.
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Answer:
Explanation:
The internal energy of any material is calculated as the sum of kinetic and potential energy of randomly distributed molecules.
This energy depends on temperature as well, if the temperature will increase the randomness will also increase hence will be the internal energy.
If any work is done on the system, then also the internal energy of the system is increased.
Answer:
Explanation:
Given
Passenger feels the seat of the car Pushing upward with a force equal to five times her weight
Therefore
it is given
where N=normal reaction
thus
B. 0 K
C. 41 K
D. 278 K
Answer : The correct option is, (D) 278 K
Explanation :
We are given temperature .
Now the conversion factor used for the temperature is,
where, K is kelvin and is Celsius.
Now put the value of temperature, we get
Therefore, the temperature 278 K is equal to the