Ginger sent 18 text messages yesterday Jerry sent 4 more than twice as many messages as Ginger sent. Kyle sent 15 fewer messages than Jerry. How many text messages did Jerry and Kyle send?

Answers

Answer 1
Answer:

Applying algebra, we can conclude that: Jerry sent 40 messages, and Kyle sent 25 messages.

How to find the number of messages using algebra?

Let's use algebra to solve this problem.

Let's represent the number of messages Ginger sent as "G," the number of messages Jerry sent as "J," and the number of messages Kyle sent as "K."

We are given the following information:

Ginger sent 18 text messages, so G = 18.

Jerry sent 4 more than twice as many messages as Ginger sent, so J = 2G + 4.

Kyle sent 15 fewer messages than Jerry, so K = J - 15.

Now, let's substitute the value of G from the first equation into the second equation to find the value of J:

J = 2 * 18 + 4

J = 36 + 4

J = 40

Now that we know Jerry sent 40 messages, we can find Kyle's number of messages using the third equation:

K = 40 - 15

K = 25

So, Jerry sent 40 messages, and Kyle sent 25 messages.

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Answer 2
Answer: So...
G sent 18
J sent 4+2(18)
K sent -15 of J

So...
18 times 2 is 36. Then add 4 to get 40. 
So, Jerry sent 40

then subtract 15 to 40... 40-15... which equals 25

Jerry is 40 texts
Kyle is 25 texts.
I hope this helps :)


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According to the pedometer i move 27 5/8 inches when i walk How many feet i will travel in 96 steps?

Answers

I am assuming that is how far you move per step? So, what I did was first multiply 27 5/8 by your 96 steps ( I also converted 5/8 into a decimal so it would be easier so it's 27.625) 27.625*96= 2,652. I divided that by 12 so I could turn that into feet instead of inches; 221 feet. 

What is 5 - 16 tenths

Answers

the answer to 5-16 tenths is 11

What is the simplest form of the expression (–12.7y – 3.1x) + 5.9y – (4.2y + x)?

Answers

The simplest form of given expression is  -11y-4.1x.

What is an expression?

Expressions in math are mathematical statements that have a minimum of two terms containing numbers or variables, or both, connected by an operator in between.

Given expression

(-12.7y-3.1x)+5.9y-(4.2y+x)

= -12.7y-3.1x+5.9y-4.2y-x

Combine like terms

= (-12.7y+5.9y-4.2y)+(-3.1x-x)

= -11y-4.1x

The simplest form of given expression is  -11y-4.1x.

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Answer:

-11y - 4.1x

Step-by-step explanation:

(-12.7y-3.1x)+5.9y-(4.2y+x)\n\n=-12.7y-3.1x+5.9y-4.2y-x\qquad\text{combine like terms}\n\n=(-12.7y+5.9y-4.2y)+(-3.1x-x)\n\n=-11y-4.1x

Miguel made a histogram to show the ages of all the participants involved in a fund-raiser. Which part of the histogram did Miguel forget to create?
Miguel forgot to choose the intervals.
Miguel forgot to create the frequency table.
Miguel forgot to create the title.
Miguel forgot to put spaces between the bars.

Answers

Answer:

Miguel forgot to create the title

Step-by-step explanation:

As given in diagram:

The histogram has intervals of 1-10,11-20,21-30,31-40 and 41-50.

Also the frequency in labelled on the y-axis from 0-7.

As there can be no space between the bars in a histogram, hence the only thing missing in the histogram is the title.

The title of histogram describes the information plotted in histogram!

Answer:

The correct option is 3.

Step-by-step explanation:

Given that Miguel made a histogram to show the ages of all the participants involved in a fund-raiser.

We need to find the part of the histogram that Miguel forget to create.

The intervals of histogram are mentioned in the given histogram. 1-10, 11-20, 21-30, 31-40, 41-50.

Frequency for each interval is cleared from the given histogram and frequency table is not a part of histogram.

The title of histogram is missing, so Miguel forgot to create the title.

In histogram, there is no space between the consecutive bars.

Therefore the correct option is 3.

Determine the equations of the vertical and horizontal asymptotes, if any, for g(x)=x-2/x^2+4x+3 A.x=-1,x=3
B.x=-1,x=-3,y=0
C.x=1,x=-3,y=0
D.x=-1,x=-3

Answers

Answer:

B. x = -1, x = -3, y = 0

Step-by-step explanation:

g(x)=(x-2)/(x^2+4x+3)\n\nvertical\ asymptote:\n\nx^2+4x+3=0\nx^2+x+3x+3=0\nx(x+1)+3(x+1)=0\n(x+1)(x+3)=0\iff x+1=0\ \vee\ x+3=0\n\n\boxed{x=-1\ \vee\ x=-3}\n\nhorizontal\ asymptote:\n\n\lim\limits_(x\to\pm\infty)(x-2)/(x^2+4x+3)=\lim\limits_(x\to\pm\infty)(x^2\left((1)/(x)-(2)/(x^2)\right))/(x^2\left(1+(4)/(x)+(3)/(x^2)\right))=\lim\limits_(x\to\pm\infty)((1)/(x)-(2)/(x^2))/(1+(4)/(x)+(3)/(x^2))=(0)/(1)=0\n\n\boxed{y=0}

I need help please and thank you

Answers

Answer:

C

Step-by-step explanation:

each face is 9 cm squared because 3 times 3 is 9

9 times 6 is 54

squared units for area and surface area

Answer: C) 54 sq cm

Step-by-step explanation:

All of the sides in the example are 3 cm each, and there are 6 sides to a cube. 3^2*6 (3 squared times 6) = 54. Because we squared 3, the answer would be C)54 sq cm.