A car's velocity changes from 32m/s to 96m/s in an 8.0-s period. what is its acceleration?

Answers

Answer 1

Answer:
|Acceleration| = (change in speed) / (time for the change)

Change in speed = (speed at the end) minus (speed at the beginning).

Change in speed = (96 m/s - 32 m/s) = 64 m/s

|Acceleration| = (64 m/s) / (8.0 sec) = 8.0 m/s²

This solution is written in terms of speed and the absolute value
of acceleration. The question gives no information regarding the
direction of motion at any time, so it's not possible to say anything
about velocity, or the direction of acceleration.

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Tidal bulge produced on Earth by the moon is causing the moon to slowly _____.move closer to Earth
shrink in size
move further from Earth
spin faster

Answers

The correct answer for the question that is being presented above is this one: "move closer to Earth." Tidal bulge produced on Earth by the moon is causing the moon to slowly move closer to Earth. Two tidal bulges are created on opposite sides of the Earth due to the moon's gravitational force and inertias counterbalance.

Answer: Move further from earth

Explanation:

What is an anemometer used to measure?

Answers

An anemometer is used to measure wind speed. It is commonly found in weather stations.

Answer:

air speed

Explanation:

took the exam

What do we mean by the main-sequence turnoff point of a star cluster, and what does it tell us? It is the spectral type of the hottest main sequence star in a star cluster, and it tells us the cluster's age. It is the point in a star cluster beyond which main sequence stars are not found, and it tells us the cluster's distance. It is the faintest and coldest main sequence star in a cluster, and it tells us the cluster's age. It is the mass of the most massive star in the star cluster, and it tells us the cluster's size.

Answers

Answer:

Explanation: The turnoff point for a star refers to the point on the Hertzsprung–Russell diagram where it leaves the main sequence after its main fuel is exhausted-the main sequence turnoff. HR diagrams for two open clusters, M67 and NGC 188, showing the main sequence turn-off at different ages.

You travel 20.0 mph for 0.500 hour, 40.0 mph for 1.00 hour, 30.0 mph for 0.500 hour, and 50.0 mph for 2.00 hours. What is the total distance traveled?

Answers

Speed is $(distance)/(time)$ , so because you already know the time(.5 + 1 + .5 + 2 = 4 hours), you want to find the distance traveled.
$(Speed)/(time) = ((distance)/(time))/(time)=(distance)/((time)/(time))=distance$
So you set it up like this:
$(20mph)/(.5\ hour)= 10 miles \n (40mph)/(1\ hour)= 40 miles\n (30mph)/(.5\ hour)= 15miles\n (50mph)/(2\ hours)=100miles \n Add\ them:\n 10+40+15+100=165miles$
You traveled 165 miles total.

Heeeelllllllpppp I need this right now Which type of friction acts on an object that is not moving?
O static fluid
O fluid friction
O sliding friction
O rolling friction

Answers

The friction which acts on the object that is not moving is static friction, so, option A is correct.

What is friction?

Between two surfaces that are sliding or attempting to slide over one another, there is a force called friction. For instance, friction makes it challenging to push a book down the floor. Friction always moves an object in a direction that is counter to the direction that it is traveling or attempting to move.

Static friction is 0 for an object at rest on a level surface. Static friction generates an equal and opposite force that holds the book at rest if you push horizontally with a small force.

The static friction force grows to meet the force as you push harder. The book eventually moves when the maximum static friction force is reached.

Thus, the friction is static.

To know more about friction:

brainly.com/question/28356847

#SPJ2

static friction

hope this helps

A papyrus scroll has 90% of the initial 14C present in it today. How old is the scroll if the half-life for 14 C is 5730 years? O 8230 years O 41.5 years O 871 years O 18.0 years O 38,100 years

Answers

Answer:

To determine the age of the papyrus scroll, we can use the concept of radioactive decay and the half-life of 14C.

The half-life of 14C is 5730 years, which means that after each 5730-year period, half of the 14C in a sample decays. Since the papyrus scroll has 90% of the initial 14C remaining, it means that 10% has decayed.

Let X be the number of half-lives that have passed. We can calculate X using the following equation:

(1/2)^X = 10%

Now, let's solve for X:

X = log(10%) / log(1/2)

X ≈ 3.32

So, approximately 3.32 half-lives have passed.

Now, we can calculate the age of the scroll:

Age = Number of half-lives * Half-life

Age = 3.32 * 5730 years ≈ 19000.6 years

Rounded to the nearest year, the age of the papyrus scroll is approximately 19,001 years.

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A car traveling in a straight line has a velocity of 6m/s at some instant. After 6.32s its velocity is 13.2m/s . What is the average acceleration in this time interval?