what is conduction, convection and infrared radiation in relation to heat transfers?

Answers

Answer 1

Answer: Conduction . . . . .
You put a spoon into a cup of really hot coffee. After a couple of minutes,
the top of the spoon is too hot to handle. The spoon CONDUCTED the heat
from the hot liquid up to the other end.
No material moved. The heat just flowed through the material.

Convection . . . . .
You put a pot of cold water on the stove and turn on the heat. The flame
heats the water at the bottom of the pot. The heated water rises from the
bottom, and cold water from the top sinks to the bottom. Hot fluid rising,
cold fluid sinking, that's CONVECTION.
Material moved, carrying heat from place to place with it.

Radiation . . . . .
-- You come into the house on a cold day, and there's a fireplace burning
across the room. Looking at the fire, you feel heat on your face, but not on
your back, and the room is still cold.
-- The sun produces a lot of heat. Somehow, it gets to the Earth, although
there's nothing in space to carry it.
-- Heat, light, and radio don't need anything to carry them. They can RADIATE
through empty space, as electromagnetic waves.
When the waves are heat, they're called Infrared waves.

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= 4 / 1
= 4Hz

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Answers

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A conducting coil of 1850 turns is connected to a galvanometer, and the total resistance of the circuit is 30 Ω. The area of each turn is 4.00 × 10-4 m2. This coil is moved from a region where the magnetic field is zero into a region where it is nonzero, the normal to the coil being kept parallel to the magnetic field. The amount of charge that is induced to flow around the circuit is measured to be 8.0 × 10-3 C. Find the magnitude of the magnetic field.

Answers

Answer:

0.324 T

Explanation:

Parameters given:

Number of turns, N = 1850

Resistance, R = 30Ω

Area of each turn, A = $4.00 * 10^(-4) m^2$

Charge in the circuit, q = $8.0 * 10^(-3) C$

The induced EMF in the coil is given as:

$V = (-NBA)/(t)$

EMF is also given in terms of current, I, and resistance, R, as:

V = IR = $(-NBA)/(t)$

=> $I*R*t = -NBA$

Charge, q, is the product of current and time. Hence:

It = q

=> $q*R = -NBA$

Hence, magnetic field, B, will be:

$B = (qR)/(-NA)$

$B = (8 * 10^(-3) * 30)/(-1850 * 4 * 10^(-4)) \n\n\nB = -0.324 T$

The magnitude of magnetic field, |B| will be |-0.324| = 0.324 T

A magnetic field forms around a moving electric charge, resulting in a magnetic field. Which does this describe?

A.
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B.
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C.
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D.
how a magnetic field can be used to generate electrons

Answers

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