Fifth grade 120 dollars Sixth grade 180 dollars Seventh grade 240 dollars Eighth grade 300 dollars. a.Write three statements that the principal could makewhen comparing the goals each grade has set. b. The teachers set a goal of $225. Write two statements the principal could use to compare this goal to the eighth graders' goal

Answers

Answer 1
Answer:

The statements that the principal could make when comparing the goals each grade has set are: 7th-grade plan to raise double the 5th grade, 6th-grade plan to raise (3)/(2) 5th grade.6th-grade plan to raise (2)/(3) of 8th grade.

How do we compare numbers?
A comparison statement is, in general, just a statement that compares two quantities or values. For instance, "If we add x apples to 3 apples, then the total number of apples is less than 10 apples" or "Mary's height is the same as Milly's height."

In the given question, we have:

The amount with 5th grade is 120 dollars

The amount with 6th grade is 180 dollars

The amount with 7th grade is 240 dollars

The amount with 8th grade is 300 dollars

So, When we double that with 5th grade will be 240 dollar

Hence, The first statement can be a 7th-grade plan to raise double the 5th-grade.

Similarly,

If we multiply (3)/(2) by the amount of 5th grade, we get 180 dollars.

and, when we multiply two-thirds of the 8th-grade amount, we get 180 dollars.

Hence, The three statements that we can write are:

7th-grade plan to raise double the 5th grade.

6th-grade plan to raise (3)/(2) 5th grade.

6th-grade plan to raise (2)/(3) of 8th grade.

(b)The two statements that could use to compare the goal to 8th graders are:

6th-grade plan to raise (2)/(3) of 8th grade.

8th-grade plan multiplied by (4)/(5) gives 7th grade plan.

When we multiply 300 by (4)/(5) the amount we get 240 dollars.

Hence, The statement that the principal could use to compare the goal to the 8th grader's goal is:

6th-grade plan to raise (2)/(3) of 8th grade.

8th-grade plan multiplied by (4)/(5) gives 7th grade plan.

To learn more about comparing numbers visit:

brainly.com/question/28441046

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Answer 2
Answer: 1. The higher the grade, the higher the goal2. The goal increases by 60$ each time3. All the goals are bigger than 100$

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Answers

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A projectile with an initial velocity of 48 feet per second is launched from a building 190 feet tall. The path of the projectile is modeled using the equation h(t) = –16t2 + 48t + 190.What is the maximum height of the projectile?
A. 82 feet
B. 190 feet
C. 226 feet
D. 250 feet

Answers

Answer:

Option c is correct

226 feet  is the maximum height of the projectile.

Step-by-step explanation:

A quadratic equation y=ax^2+bx+c,   ....[1]

then the axis of symmetry is given by:

x = -(b)/(2a)

As per the statement:

The path of the projectile is modeled using the equation :

h(t) = -16t^2+48t+190            ....[2]

where, h(t) is the height after t time.

On comparing with [1] we have;

a = -16 and b = 48

then;

t = -(48)/(2(-16)) = (48)/(32) = 1.5 sec

Substitute this in [2]  we have;

h(1.5) = -16(1.5)^2+48(1.5)+190  

h(1.5) = -36+72+190  

Simplify:

h(1.5) = 226 ft

Therefore, the maximum height of the projectile at 1.5 sec is, 226 feet.

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Is 25 pounds bigger than or less than 384 fluid ounces

Answers

Let's find out together.

There are sixteen ounces in a pound, so 25 pounds (lbs) is 400 ounces (oz). 400>384. 

So, 25 lbs is bigger than 384 oz.

25 Pounds is bigger:)

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Answers

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