What does 50 tens equal

Answers

Answer 1
Answer: 50*10 so it would equal 500

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Factor the equation.X2-15x+50=0
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a sailfish can swim up to 1 mile per hour less than one fifth the top speed of a peregrine falcon. Find the top speed that a sailfish can swim?

Answers

top speed of a peregrine falcon is 240 miles per hour

 240 x 1/5 = 48

48-1 = 47

 sailfish can swim 47 miles per hour

Answer: The top speed that a sailfish can swim at ((x)/(5)-1)\ mph

Step-by-step explanation:

Since we have given that

Top speed of a peregrine falcon be 'x'.

One fifth the top speed of a peregrine falcon would be

(1)/(5)x

1 mile per hour less than the above is expressed as

(1)/(5)x-1

According to question, the top speed that a sailfish can swim would be

(1)/(5)x-1

Hence, the top speed that a sailfish can swim at ((x)/(5)-1)\ mph

By first calculating the size of angle LMN,calculate the area of triangle MNL.
You must show all your working.
ML is 4.8cm
LN is 7.2 cm
angle N is 38 degrees

Answers

9514 1404 393

Answer:

  16.66 cm²  or  8.49 cm²

Step-by-step explanation:

The law of sines is useful for this.

  sin(N)/LM = sin(M)/LN

  M = arcsin(sin(N)×LN/LM) = arcsin(sin(38°)×7.2/4.8)

  M =67.44°  or  112.56°

Angle L is the remaining angle, so will have one of two measures:

  L1 = 180° -38° -67.44° = 74.56°

The area of that triangle is ...

  A = (1/2)LM×LN×sin(74.56°) ≈ 16.66 . . . . cm²

or ...

  L2 = 180° -38° -112.56° = 29.44°

The area of that triangle is ...

  A = (1/2)LM×LN×sin(29.44°) ≈ 8.49 . . . . cm²

Final answer:

To calculate the area of triangle MNL, first calculate the size of angle LMN using the Cosine Rule. Then use that angle and the known side lengths in the formula for the area of a triangle (Area = 0.5 * a * b * sin(C)) to find the area.

Explanation:

To solve this, you need to first calculate the size of angle LMN. This can be done using the Cosine Rule, which states that cos(C) = (a² + b² - c²) / 2ab, where a and b are the sides enclosing angle C. Here, angle C would be LMN, and sides a and b would be ML and LN.

Applying the values from your question, the cosine of LMN would be cos(LMN) = (4.8² + 7.2² - 38²) / (2 * 4.8 * 7.2). After calculating the cosine of the angle, you can find the angle itself using the inverse cosine function, or arccos.

Once you have the size of angle LMN, you can calculate the area of the triangle using the formula Area = 0.5 * a * b * sin(C), where a and b are sides of the triangle and C is the included angle. So, the area of triangle MNL would be Area = 0.5 * ML * LN * sin(LMN).

Learn more about Triangle Area Calculation here:

brainly.com/question/21036800

#SPJ12

As shown in the diagram below, CD is a median of triangle ABC.

Answers

Always true is a statement (1) \overline{AD}=\overline{DB}

The circle graph shows Tommy Blox spent the money he earned last summer. If he spent $80 on entertainment, how much did Tommy earn altogether?

Answers

Answer:

Tommy earned $250 altogether.

Step-by-step explanation:

Let the total earning of Tommy be 'x' dollars.

Given:

Money spent on entertainment = $80

From the circle shown below:

Percent spent on clothes = 19%

Percent spent on food = 25%

Percent spent on other things = 14%

Percent of savings = 10%

Addition of all percents = 100%

19% + 25% + 10% + 14% + % Entertainment = 100%

⇒ 68% + % Entertainment = 100%

% Entertainment = 100% - 68% = 32%

Therefore, as per question:

32\%\ of\ x=\$80\n\n0.32x=80\n\nx=(80)/(0.32)\n\nx=\$250\n

Hence, Tommy earned $250 altogether.

What is
x=5y-1
x+2y=13

Answers

x=5y-1
x+2y=13 => 5y -1 +2y = 13 => 7y = 14 => y = 2 => x = 9;

Answer: x = 9, y = 2

Step-by-step explanation:

plug in values and solve.

three bags of potatoes and four cases of corn cost $40. Five bags of potatoes and two cases of corn cost $34. Find the cost of one bag of potatoes and the cost of one case of corn.

Answers

Use variables and set up equations.

3p + 4c = 40 \n 5p + 2c = 34

Next, get one variable with equal coefficients.

3p + 4c = 40 \n 10p + 4c = 68\ (multiplied\ both\ sides\ by\ 2)

Then get it alone on one side.

4c = 40-3p \n 4c = 48-10p

Now we can use substitution. Since 40-3p = 4c, substitute 40-3p for 4c in the other equation and you'll get an equation with just one variable to simplify and solve.

40-3p = 68-10p \n 40+7p = 68 \n 7p = 28 \n \boxed{p = 4}

We can then use p = 4 in an earlier equation to find c.

5p + 2c = 34 \n 5*4 + 2c = 34 \n 20 + 2c = 34 \n 2c = 14 \n \boxed{c=7}

3p + 4c = 40 ⇒ 15p + 20c = 200
5p + 2c = 34 ⇒ 15p +   6c = 102
                                    14c = 98
                                     14     14
                                        c = 7
                            5p + 2(7) = 34
                              5p + 14 = 34
                                    - 14  - 14
                                      5p = 20
                                       5      5
                                        p = 4
                                  (p, c) = (4, 7)