10+-2f^2+-6+7+-2f^2+-9f

Answers

Answer 1

Answer: $10+-2f^2+-6+7+-2f^2+-9f = 10-2f^2 -6+7-2f^2 -9f \n\n= -2f^2 -2f^2 -9f+10-6+7= \boxed {-4f^2 -9f +11}$

Answer 2

Answer: $10+(-2f^(2))+(-6)+7+(-2f^(2))+(-9f)=10-2f^2+1-2f^2-9f$

$-4f^2-9f+11=-(4f^2+9f-11)$

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Max is thinking of a double fact. It has a sum greater than 10 but less than 13. What number fact could it be?
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Please help don't really understand pic below

Answers

to simplify the equation just subtract 9-7 which simplifies to 11x+2

If you're just simplifying the expression and not solving, it would equal 11x + 2. You just have to combine like terms, so 9 - 7 and then add the 11x onto it.

The equation x^2/121+y^2/1=1 represents an ellipse. Which points are the vertices of the ellipse? (-11,0) and (11,0). (-1,0) and (1,0). (0,-11) and (0,11). (0,-1) and (0,1)

Answers

Answer:(-11,0) and (11,0)

The 6:00 am temperatures for four consecutive days in the town of Lincoln were -12.1 C, -7.8C, -14.3 C, and -7.2C. What was the average 6:00 am temperature for the four days

Answers

To find the average you have to add all the numbers up together, and then divide the sum of those number by how many numbers there were.
1) -12.1+-7.8+-14.3+-7.2= -41.4
2) -41.4/4 = -10.35
3) Final Answer= -10.35 C

Final answer:

The average of the temperatures -12.1 C, -7.8 C, -14.3 C and -7.2 C is calculated by adding all temperatures together then dividing by the number of values. The average 6:00 am temperature over the four days in Lincoln is -10.35 C.

Explanation:

The subject of this question is mathematics, specifically statistics. The student needs to calculate the average of the daily 6:00 am temperatures over four days in the town of Lincoln. The temperatures are -12.1 C, -7.8C, -14.3 C, and -7.2C.

The average temperature can be found by adding all the temperatures together then dividing by the number of temperatures measured. Here's how:

Add the temperatures together: -12.1 C + -7.8 C + -14.3 C + -7.2 C = -41.4 C
Then divide the total by the number of temperatures: -41.4 C ÷ 4 = -10.35 C

Therefore, the average 6:00 am temperature over the four days in the town of Lincoln is -10.35 C.

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In the 1st generation, there are 3 rabbits in a meadow.

Answers

Answer: Option C

$a_n=3(6)^(n-1)$

Step-by-step explanation:

The number of rabbits in each generation can be modeled using a geometric sequence of the form:

$a_n=a_1(r)^(n-1)$

Where $a_1$ is the first term of the sequence, $a_n$ is the ninth term of the series, r is the common ratio

To find the proportion we divide the consecutive terms of the sequence as shown

$(18)/(3)=6\n\n(108)/(18)=6$

Then the common ratio is: $r=6$

The first term of the series is: $a_1=3$

Then the explicit formula is:

$a_n=3(6)^(n-1)$

The answer is: Option C

Answer: I think the answer is C.

Step-by-step explanation:I don't really know how to explain but I think that's correct.

What percent of 76 is 19?

Answers

19/76 = x/100
76x = 1900
x = 25

25%

7.5 is the answer to your question

Emily has a road map with a key that shows an Inch on the map equals 5 miles of actual distance. she will drive on two roads to get to the beach. One road is 7 inches long on the map. The other road is 5 inches long. What is the actual distance Emily will drive to the beach? Write the rule you used to find the actual distance.

Answers

Emily travelled 35 miles and 25 miles in actual distance.

What is scale in maps?

Scale is defined as the ratio of the length of any object on a model (blueprint) to the actual length of the same object in the real world.

Given that a map is showing a scale of 1 in = 5 miles, we need to find the actual distance if Emily travel 7 inches and 5 inches according to the map,

So,

Since 1 in = 5 mi

Therefore,

7 in = 5 × 7 = 35 miles

Similarly,

5 in = 5 × 5 = 25 miles

Hence Emily travelled 35 miles and 25 miles in actual distance.

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1 inch = 5 miles , 2 inches= 10 miles...7 inches=35 miles

35 miles plus 25 miles =60 miles

5 inches is 25 miles

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Jack and Luke were wrapping presents. Jack was able to wrap presents at a constant rate of 3 presents every 15 min. Luke was able to wrap presents at a constant rate of 5 presents every 20 min. Each boy had 20 presents to wrap, and the boys started wrapping presents at the same time.Write an equation to find the rate each boy wraps presents. You may use y=kx or w=rt (4 points 2 for each)