Okay, let's see...
The problem is asking for a linear equation most likely in the form of y=mx+b
y is another way to say f(x)
m = slope
b = y intercept
Let's start with the y intercept first.
Y intercept means ' When does the line touch (intercept) the y axis.
In this case, if you look at the graph, the line touches the y axis at -1.
-1 will replaces b
To find the slope we are going to take 2 precise points from the graph.
Lets use (0,-1) and (-6,4)
To find the slope, we're going to use
4 - (-1) / -6 - 0
Solve, our slope is 5/-6
That is our m
Our final equation is
If you are you looking for 289-352=-63
Here is another way 352-289=63
They switched so if you want it in a negative there you go if you want it in a positive it is the second one.
A. y = 3x + 4
B. y = -7x
C. x = 7y
D. x = y + 7
Answer:
B
Step-by-step explanation:
Answer:
Refer below for the explanation.
Step-by-step explanation:
As per the question we are asked to combine f(n) = 11 and g(n) = −2(n − 1), both of them to create arithmetic sequence and solve for 31st term.
So first we are about to solve and combine both of the equation which becomes ,
Fn = 11 -2(n-1)
Fn=11-2(n-1)
F31=-49
Fn=11-2(n-1)
F31=-51
Fn=11+2(n-1)
F31=71
Fn=11+2(n-1)
F31=73
To create an arithmetic sequence using the given functions, we add the functions together and substitute the desired term. The 31st term of the arithmetic sequence is -49.
To combine the functions f(n) = 11 and g(n) = -2(n - 1) into an arithmetic sequence, we need to find the common difference between the terms. The common difference between the terms in an arithmetic sequence is obtained by subtracting one term from the previous term. In this case, the common difference is g(n). So, the arithmetic sequence can be expressed as an = f(n) + g(n).
For the 31st term, we substitute n = 31 into the equation and calculate:
a31 = f(31) + g(31)
a31 = 11 + [-2(31 - 1)]
a31 = 11 + [-2(30)]
a31 = 11 + [-60]
a31 = -49
Therefore, the 31st term of the arithmetic sequence an is -49.
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