Answer:
v= −2c+2s / a^2
Step-by-step explanation:
a. = −9
b. = −6
c. = 4
d. = −4
If a = b x c then c = a/b
So the number you're looking for is -6 / 2/3, which is -6 * 3/2 = -9
3x − 2y + 2z = 2
5x − 8y − 4z = 1
Answer:
No solutions
Step-by-step explanation:
We need to eliminate one of the variables to solve the system. To do so, let's multiply the first equation by 8, the second equation by 4
The system becomes:
Add (1) and (2), subtract (3) from (2) to eliminate y
Then multiply the equation (5) by 4 to compare with(4)
Comparing the equations (4) and (5) we see it has no solutions as both variables have same coefficient but with different sum, 28≠40
Answer:
inconsistent; none
Answer:
*Parabola that opens up
*y-intercept is 2
*x-intercepts are -1/3 and -2
*vertex is (-7/6 , -25/12)
Step-by-step explanation:
I will describe what this graph looks like.
First, the graph is quadratic because it is in the form ax² + bx + c. The function must be in the shape of a parabola. Parabolas look like a "U" shape.
Whether "a" is negative or positive represents of the parabola opens up or down. Since "3" is positive, the parabola opens up.
"c" represents the y-intercept. The y-intercept is when the graph touches the y-axis. The function must have a y-intercept of positive 2.
We can also find its x-intercepts, also called roots/zeroes, by substituting into the quadratic formula (Ignore the Â).
Using the form ax² + bx + c, we know:
a=3; b=7; c=2
Substitute into the formula.
Split the equation at the ± sign.
The graph has x-intercepts -2 and -1/3.
We can find the vertex of the graph. It is the part of the parabola that is the lowest (or highest, is it opens down).
Find the midpoint of the x-intercepts for the vertex x-coordinate:
(-1/3 - 2)/2 = (-1/3 - 6/3)/2 = (-7/3)*(1/2) = -7/6 = -1.167 = x
Substitute the vertex x-coordinate into the formula to find the "y" in vertex.
y=3x²+7x+2
y=3(-7/6)²+7(-7/6)+2
y= 147/36 + (-49/6) + 2
y= 147/36 + (-294/36) + 72/36
y= (147-294+72)/36
y = -75/36
y = -25/12 = -2.083
The vertex is (-7/6 , -25/12) OR about (-1.167, - 2.083).
The function represents a parabola. This is graphed by creating a series of (x,y) pairs and plotting them. The resultant shape is a parabola opening upwards.
The graph described by the function is a parabola as this is a quadratic function. To depict this graph, you plot specific points determined by varying the values of x and calculating the corresponding y values.
For instance, if x is 0, y would be 2 ( ), so (0,2) is one point on the graph. You continue this process with different x values to generate a series of (x,y) pairs, which you can then plot on a graph. Once you've plotted these points, you can connect them to see the graphical representation of the function.
In this case, you would get a parabola opening upwards since the coefficient of the term is positive.
#SPJ12