Log11 1/121=-x-4 stupid math

Answers

Answer 1

Answer: $log_(11)121=-x-4\n\nlog_(11)11^2=-x-4\n\n2=-x-4\n\nx=-4-2\n\nx=-6$

Answer 2

Answer: $log_(11)(1)/(121)=-x-4\n \n log_(11)11^(-2)=-x-4\n \n 11^(-x-4)=11^(-2)\n \n -x-4=-2\n \n -x=-2+4\n \n -x=2\n \n \boxed{x=-2}$

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1+4=5
2+5=12
3+6=21
8+11=

Answers

There's a pattern
You see, like in this problem:
2 + 5 = 12
They did 5 times 2 = 10, plus da 2 in da problem = 12.
Same with 3 + 6 = 21, 6 times 3 = 18, 18 plus da 3 given in da problem = 21.
Just like 1 + 4 = 5, 4 times 1 = 4, plus da 1 in da problem = 5.
SO,
with that strategy, 8 +11 = 96, because 8 times 11 = 88, plus da 8 given in da problem = 96.
I hope I helped! =D

Twice a number increased by 5?? in algebraic expression

Answers

To write this as an algebraic expression, remember that twice a number means that 2 is being multiplied by a number. Since we are not solving, we can just use the variable n to represent the number that is being multiplied by 2. Finally, adding 5 to the number we will get the expression 2n + 5.

2x+5 would be the equation

x is the "number" that is unknown, it's what's called a variable. Because you need two times a number(x) you put a coefficient of 2 in front of it, then simply add 5.

Examples with known variable values:
2(4)+5=13
2(2)+5=9

If Mary deposits $275 in principal at an interest rate of 3.2 percent, how much interest will she earn in one year

Answers

I know 3.2% of $275 is $8.8
so i think $283.8

Factor completely 36x^2y^3 − 9xy^2.9y^2(4x^2y − x)
9xy^2(4xy − 1)
9xy(4xy^2 − y)
9x(4xy^2 − y^2)

Answers

Your answer is the second one

Answer:

i think it might be D) 9x(4xy^2 − y^2)

Step-by-step explanation:

Multiply. start fraction k plus 3 over 4 k minus 2 end fraction dot left parenthesis 12 k squared plus 2 k minus 4 right parenthesis

Answers

Answer:

$\therefore ((k+3))/((4k-2)).(12k^2+2k-4)=3k^2+11k+6$

Step-by-step explanation:

Factorization of a Quadratic polynomial:

In order to factorize $ax^2+bx+c$ we have to find out the numbers p and q such that, p+q = b and pq=ac.

Finding the two integers p and q, we rewrite the middle term of the quadratic as px+qx. Then by grouping of the terms we can get desired factors.

Multiplication of two binomial:

(a+b)(c+d)

=a(c+d)+b(c+d)

=(ac+ad)+(bc+bd)

=ac+ad+bc+bd

Given that,

$((k+3))/((4k-2)).(12k^2+2k-4)$

$=((k+3))/(2(2k-1)).2(6k^2+k-2)$ [ taking common 2]

$=((k+3))/((2k-1)).(6k^2+k-2)$ [ cancel 2]

$=((k+3))/((2k-1)).(6k^2+4k-3k-2)$

$=((k+3))/((2k-1)).\{2k(3k+2)-1(3k+2)\}$

$=((k+3))/((2k-1)).(3k+2)(2k-1)$

$=(k+3).(3k+2)$

$=3k^2+9k+2k+6$

$=3k^2+11k+6$

$\therefore ((k+3))/((4k-2)).(12k^2+2k-4)=3k^2+11k+6$

Gloria has a lunch account in the school cafeteria. The balance, f(x), in her account can be represented by the function f(x) = –1.50x + 40, where x is the number of meals purchased. Suppose –1.50 changed to –2.75. What does this mean in the context of the problem?

Answers

f(x) = -1.50x + 40.....basically, this is saying that Gloria has 40 bucks in her lunch account and each meal costs her 1.50.

By changing the -1.50 to -2.75 means she is paying more for her meals...the cost of a meal went up from 1.50 to 2.75.

Final answer:

The change from -1.50 to -2.75 indicates an increase in the cost of the meals. Consequently, Gloria's lunch account balance will deplete faster now.

Explanation:

In the context of this problem, f(x) = –1.50x + 40 represents how much money Gloria has left in her lunch account after purchasing x number of meals. The coefficient of x, -1.50, indicates the cost per meal. If –1.50 changed to –2.75, it would mean that the cost of each meal has increased from $1.50 to $2.75. Consequently, Gloria's account balance would decrease faster, signifying that less meals can now be purchased with the same amount of money.

Learn more about linear equations here:

brainly.com/question/32634451

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