A bus slows down uniformly from 75.0 km/h to 0 km/h in 21 s. How far does it travel before stopping?

Answers

Answer 1
Answer:

As per the question,the bus slows down uniformly from 75 km/h to 0 km/h.

Hence  the initial velocity of the bus[ u]=75 km/hr.

             the final velocity of the bus [v]=0 km/h

             the taken by the bus to stop [t]=21 s

we know that 1 km= 1000 m and 1 hour =3600 second.

Hence 75 km/h =75*(1000 m)/(3600s)

                          =20.83 m/s

we are asked to calculate the stopping distance.

From  equation of kinematics we know that-

                                    v= u +at   where a is the acceleration of the particle.

we have v= 0 km/h  = 0 m/s and u= 75 km/h =20.83 m/s

              t = 21 s

  Putting these values in above equation  we get-

                                 0 = 20.83 +a×21

                                ⇒ a×21 = -20.83 m/s

                                ⇒a=  -[20.83]÷21

                                     = -0.9919 m/s^2    [ Here negative sign indicates that particle is decelerating ]

Again from the equation of kinematics we  know that-

                                 s = ut +(1)/(2) at^2

Here s is the distance traveled. Putting the above quantities we get-

                                      s = 20.83 *21 -(1)/(2) 0.9919 *[21^2]

                                            s = 218.7 metre.  [ans]

Hence the bus will stop after a distance of 218.7 m.


                                 




Answer 2
Answer:
1 hour = 3,600 seconds
1 km = 1,000 meters

75 km/hour = (75,000/3,600) m/s =  20-5/6 m/s

The average speed of the bus while it slows down is

                                   (1/2)(20-5/6 + 0) = 10-5/12 m/s .

Traveling at an average of 10-5/12 m/s for 21 seconds,
the bus covers

                         (10-5/12) x (21) =  218.75 meters .

                  

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You throw a rock out of a 7th story window. you time that it takes 3.7 seconds to hit the ground, and measure that it hit the ground 115 m from the base of the building? How fast must you have thrown the rock?
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If you had thrown it at the same speed but at the 28th floor, how far from the base of the building would it land?

Answers

1) 31.1 m/s

The rock has been thrown straight out of the window: its motion on the horizontal direction is simply a uniform motion, with constant speed v, because no forces act in the horizontal direction. The speed in a uniform motion is given by

v=(S)/(t)

where S is the distance traveled and t the time taken.

In this case, the distance by the rock before hitting the ground is S=115 m and the time taken is t=3.7 s, so the initial speed is given by

v=(115 m)/(3.7 s)=31.1 m/s


2) 67.1 m

In this part of the problem we are only interested in the vertical motion of the rock. The vertical motion is a uniformly accelerated motion, with constant acceleration a=9.8 m/s^2 (acceleration of gravity) towards the ground. In a uniformly accelerated motion, the distance traveled by the object is given by

S=(1)/(2)at^2

where t is the time. Substituting a=9.8 m/s^2 and t=3.7 s, we can find S, the vertical distance covered by the rock, which corresponds to the height of the 7th floor:

S=(1)/(2)(9.8 m/s^2)(3.7 s)^2=67.1 m


3) 230.1 m

The height of the 7th floor is 67.1 m. So we can assume that the height of each floor is

h=(67.1 m)/(7)=9.6 m

And so, the height of the 28th floor is

h=28\cdot 9.6 m=268.8 m

We can find the total time of the fall in this case by using the same formula of the previous part:

S=(1)/(2)at^2

In this case, S=268.8 m, so we can re-arrange the formula to find t

t=\sqrt{(2S)/(g)}=\sqrt{(2(268.8 m))/(9.8 m/s^2)}=7.4 s

And now we can consider the motion of the rock on the horizontal direction: we know that the rock travels at a constant speed of v=31.1 m/s, so the distance traveled is

S=vt=(31.1 m/s)(7.4 s)=230.1 m

And this is how far from the building the rock lands.

speed = distance/time taken 
             115/3.7 =31.08m/s^2

Lime your sus you walked past the body but didn't report

Answers

Answer:

You Got me im Imposter

Explanation:

Matter is __________. A. the amount of energy contained within an object B. a measure of the force gravity exerts on objects C. something that has mass and occupies space D. a measure of an object's inertial force Please

Answers

Matter can be defined as something that has mass and occupies space. They are present in the atmosphere in different phases. Thus, the correct option is C.

What is Matter?

Matter is any substance which is made up of various types of particles that occupies some physical space and has mass. According to the modern physics, there are various types of particles with each having a specific mass and size. The most common examples of these material particles are electrons, protons and neutrons.

Matter is present in different phases in the atmosphere. The three phases are solids, liquids, and gases. All of these phases show mass and occupies some space.

Therefore, the correct option is C.

Learn more about Matter here:

brainly.com/question/29232090

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Answer: C

Explanation:

Matter is anything that has mass and takes up space. People, paper, goats, chairs and even water is Matter!

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Answers

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