The solution is, 14 tiles does Joe need.
Area is the measure of a region's size on a surface. The area of a plane region or plane area refers to the area of a shape or planar lamina, while surface area refers to the area of an open surface or the boundary of a three-dimensional object.
here, we have,
given that,
Joe's bathroom floor is 5 feet wide and 8 feet long. He will cover the floor with 3" square tiles.
so first find area
area=legnth times width
5=width
8=legnth
5 times 8=40
so, we have,
area=40
3 area times x number of tiles=40
divide both sides by 3
x=40/3
x=13 and 1/3
since you can't buy 1/3 tiile
round up
x=14
answer is 14 tiles does Joe need.
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Step-by-step explanation:
KE = ½ mv²
KE = ½ (800 N / 10 m/s²) (6 m/s)²
KE = 1440 J
(+ or -) _ _ _ _ . _ _
Answer:
14.14 ft.
Step-by-step explanation:
where a and b are constants.
The cost of travelling 100 miles is £82. the cost of travelling 250 miles is £157
a find out the value of a and b
b work out the cost of hiring a lorry to travel 300 miles
Please show working out clearly, ill award a brainliest answer!!!!!
Answer:
Part a) a = 32 and b = 0.5
Part b) £182 is the cost of hiring.
Step-by-step explanation:
Given expression is C = a + bn
where C is the cost of hiring a lorry, n is the distance covered and a, b are two constants.
Part a).
We have to find the constants a and b.
Now we will find the system of equations to find the value of constants.
The cost of travelling 100 miles is £82.
82 = a + 100b ---------(1)
The cost of travelling 250 miles is £157
157 = a + 250b --------(2)
Now we will subtract equation 2 from 1.
157 - 82 = (a + 250b) - (a + 100b)
75 = 150b
b =
Now we put the value of b in equation 1
82 = a + 100×(0.5)
82 = a + 50
a = 82 - 50 = 32
a = 32 and b = 0.5
Part b).
We have to find the cost of hiring a lorry to travel 300 miles.
C = a + bn
C = 32 + (0.5)(300)
C = 32 + 150
C = £182
B. The surface area of "B" is greater than the surface area of "A."
C. The volume of "B" is greater than the volume of "A."
D. The volume of "A" is greater than the volume of "B."