(5,2)
5=x
y=2
5-3=2
hope that helps
y=x^2-4x+4
How many cycles will occur between t=2 and t=3.5 seconds?
The number of cycles that will occur between t = 2 and t = 3.5 seconds is 384.
Given, y = 8 sin(512πt)
where t = time in seconds.
The standard equation of a sine wave is:
y = A sin(2πfx + B) + C
where A exists the amplitude
f exists the frequency
B exists the phase shift
C is the vertical offset.
In this case:
2πf = 512π
f = 256
This means there are 256 cycles per second.
The number of cycles between t = 2 and t = 3.5 exists:
(3.5 − 2) × 256
= 384
Therefore, the number of cycles that will occur between t = 2 and t = 3.5 seconds is 384.
To learn more about the standard equation of a sine wave
#SPJ2
Answer:
384
Step-by-step explanation:
Standard equation of a sine wave is:
y = A sin(2πf x + B) + C
where A is the amplitude, f is the frequency, B is the phase shift, and C is the vertical offset.
In this case:
2πf = 512π
f = 256
This means there are 256 cycles per second. The number of cycles between t = 2 and t = 3.5 is:
(3.5 − 2) × 256
384
Answer:
$702.53
Step-by-step explanation:
Start with Jose's initial balance.
He wrote checks, so we have to subtract the total amount the checks were worth. Let's first add the three amounts.
Solve.
Subtract the total amount of the checks from Jose's initial balance.
Solve.
The amount above is now what is in Jose's checking account.
But, he also deposited money, meaning he put money in his checking account. Now, let's add the three amounts he deposited.
Solve.
The amount above is what Jose adds to his checking out.
Add the total value of the deposited money and his new balance.
Solve.
x^2-2x-5=0
Opposite sides are parallel.
B.
All sides are the same length.
C.
Only one pair of sides is parallel.
D.
All sides are different lengths.