The number of girls at middle school Cyber summer camp was six more than twice the number of boys. The total of 156 middle school at the camp. How to use the 5-d process? To find the number of boys and girls at the camp.
Answers
boys: 75
4x +6 = 156
4x = 150
x = 37.5
2x = 75
girls: 75 + 6
boys: x
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Circle Q has the central angle ∠AQB with a measure of 55°. Which of the following option is not true? AB is a minor arc the measure of AB=110 degrees The center of the circle point is Q The measure of AB=55 degrees
Pls help for brainliest answer
elizabeth asked 125 people if they can speak more than one language.36% sayed they can. how many people said they can?
Answers
170
then we add 30 to reach the number 200
170+30=200
then we add 200 to reach the number 400
200+200=400
then we add 10 to reach 410
400+10=410
The benchmark numbers are bolded...
Answers
X= cones; y= sundaes
1.80x + 3.30y = 360.90 -------(i)
x + y = 148 -----------(ii)
from (ii) y= 148-x
1.80x + 3.30(148-x) = 360.9
1.80x + 488.4 + 3.30x = 360.9
1.5x = 127.5
x = 85 cones
t= dart that hit the target
m= darts that miss the target
t+m=10
5t+3m=18
Answers
h=hits
m=miss
h+m=10
gain 5 for every hit and lose 3 for every miss
so 5 times number of hit=points from hit
-3 times number of miss=points deducted from miss
add
5h-3m=18
so we have the equations
h+m=10
5h-3m=18
multiply first equation by 3
3h+3m=30
add to first equatio
3h+3m=30
5h-3m=18 +
8h+0m=48
8h=48
divide by 8
h=6
subsitute
h+m=10
6+m=10
subtract 6
m=4
6 hits
4 miss
Let t= dart that hit the target
Let m= darts that miss the target
t+m=10 This equation is true because you throw 10 darts in one game.
5t+3m=18 This equation is true because the team got 18 points.
Now let's use substitution by solving one variable and substituting what the variable equals into the other equation.
t+m=10
m = 10-t
Now substitute 10-t as "m" in the other equation.
5t + 3(10-t) = 18
5t + 30 -3t = 18
2t = -12
t = -6
Now substitute -6 into the equation m=10-t
m = 10 - (-6)
m = 10 + 6
m = 16
Answers
Answers
15+1=1/6n+1/6n
16=1+1/6n
16=2/6n
16=1/3n
16*3/1=n
therefore, n=48.........
Answer:
n=48
Step-by-step explanation:
Answers
4 consecutive odd integers whose sum is 232 are : 55, 57, 59, 61
How to find the sum of consecutive integers?
Let the first integer be x and x is an odd number.
Let Four consecutive odd integers are;
x, x + 2, x + 4, x + 6
(x) + (x + 2) + (x + 4) + (x + 6) = 232
4x + 12 = 232
4x = 232 - 12
4x = 220
x = 220/4
x = 55
x + 2 = 55 + 2 = 57
x + 4 = 55 + 4 = 59
x + 6 = 55 + 6 = 61
The numbers are : 55, 57, 59, 61
Learn more about the concept here;
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x, x + 2, x + 4, x + 6
(x) + (x + 2) + (x + 4) + (x + 6) = 232
4x + 12 = 232
4x = 232 - 12
4x = 220
x = 220/4
x = 55
x + 2 = 55 + 2 = 57
x + 4 = 55 + 4 = 59
x + 6 = 55 + 6 = 61
so ur numbers are : 55, 57, 59, 61