b. Axons
c. Neurotransmitters
d. Thresholds
Answer:
Bayesian mimicry
Explanation:
Batesian mimicry is a form of mimicry where a harmless species has evolved to imitate the warning signals of a harmful species directed at a predator of them both. It is named after the English naturalist Henry Walter Bates, after his work on butterflies in the rainforests of Brazil.
Answer:
Mimicry
Explanation:
Mimicry can described or explained as the process whereby one organism copy the action of others and do exactly the same as that copied organism.
This is usually done when the action copied from the organism is useful in escaping from predators or being seen by other organisms as a predator and allow it to have access to the available resources.
In this case, when other organism copy the bright coloration of that small poisonous organism to drive away other organism, it is called mimicry.
In a population that is in Hardy-Weinberg equilibrium, the frequency of the dominant allele (in this case, for orange flowers) is p and the frequency of the recessive allele (for yellow flowers) is q. 48% of the population is heterozygous for the flower color alleles in this plant species under Hardy-Weinberg equilibrium. In this particular flowering plant species, orange flower color shows simple dominance over yellow flower color.
Given that 16% of the population show yellow-flower phenotypes in a population that is in Hardy-Weinberg equilibrium, we can calculate the percent of the population that is heterozygous for the flower color alleles.
Step 1: Determine the frequency of the recessive allele (q)
Since 16% of the population has yellow flowers (recessive phenotype), the frequency of the recessive homozygous genotype (qq) is 0.16. To find the frequency of the recessive allele (q), we take the square root of 0.16, which is 0.4.
Step 2: Determine the frequency of the dominant allele (p)
Using the Hardy-Weinberg equilibrium equation, p + q = 1, we can calculate the frequency of the dominant allele (p). Since q = 0.4, then p = 1 - 0.4 = 0.6.
Step 3: Calculate the percentage of heterozygous individuals (2pq)
To find the frequency of the heterozygous genotype (2pq), we multiply 2 by the frequency of p and q: 2 x 0.6 x 0.4 = 0.48.
Therefore, 48% of the population is heterozygous for the flower color alleles in this plant species under Hardy-Weinberg equilibrium.
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Answer:
The correct answer would be Pp.
The genotype of one parent is PP. Thus, it will produce only one type of allele, that is, P.
Similarly, the genotype of another parent is pp. Thus, it will produce only one type of gamete, that is, p.
The cross would produce offspring with only one type of genotype, that is, heterozygous Pp.
The phenotype of all the offspring will be purple as it is a dominant trait.
When we cross PP x pp we obtain:
Pp + Pp + Pp + Pp (we obtain four identical genotype).
Pp (heterozygote flower) is the Only genotype when we cross two different homozygotes.
The phenotype will be the purple flower since it is the dominant genotype.