Find the slope of a line perpendicular to the line whose equation is 3y + 2x = 6

Answers

Answer 1
Answer: 3y + 2x = 6\n \nthe \ slope \ intercept \ form \ is : \n \n y= mx +b \n \n3y=-2x+6 \ \ /:3\n \ny=-(2)/(3)x+(6)/(3)\n \ny=-(2)/(3)x +2 \n \n m = -(2)/(3) \n \n Answer : \ slope \ is \ m = -(2)/(3)

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Write y=2x^2+8x+5 in vertex form. Please

-9-11x=68
what does x=?

Answers

The answer would be about 5, though, the correct mathematical answer is 5.36363636. 

21.21+13.22+-13.22 what is the answer

Answers

Answer:

21.21

Step-by-step explanation:

=21.21+13.22+(-13.22)

=21.21+0

=21.21

Answer: 47.65

Step-by-step explanation:

Hope this helps:)

Graph the liner equation

Answers

      -x - y = 0
-x + x - y = x
           -y = x
           -1   -1
            y = -x

Answer:

can you help me w math?

Step-by-step explanation:

Based on the given information, what can you conclude, and why? Given: <H congruent to <L; Line HJ congruent to Line JLA. <HIJ congruent to <LKJ by ASA
B. <HIJ congruent to <JLK by SAS
D. <HIJ congruent to <LKJ by SAS

Answers

Similar triangles may or may not be congruent.

The true statement is: A. <HIJ congruent to <LKJ by ASA

The given parameters are:

\mathbf{\angle H \cong \angle L}

\mathbf{HJ \cong JL}

The above highlights imply that:

\mathbf{\angle J \cong \angle J}

This means that, the angle at point J in both shapes are also congruent.

By that, the two shapes have two congruent angles and one congruent side.

So, we can conclude that, triangles HIJ and LKJ are congruent by ASA theorem of similar triangles

Hence, (a) is true

Read more about similar and congruent triangles at:

brainly.com/question/19589236

Rewrite each expression as a sum.12. - 8x2 + 3xy - 9x - 3

13. 2ab -- 5ab2 - 9a2b

Answers

13 ). 2ab + 5ab x 2 - 18ab

2ab + 10ab - 18ab

- 6ab

Answer= - 6ab

Find the discriminant and the number of real roots for this equation 9x^2+12x+4=0

Answers

The discriminant is 0. As the discriminant is 0 it will have equal roots.

And the real root is -2/3.

What is a Quadratic Equation?

In algebra, a quadratic equation is any equation that can be rearranged in a standard form where x represents an unknown, and a, b, and c represent known numbers, where a ≠ zero.

Conclusion: If a = zero, then the equation is linear, no longer quadratic, as there's no ax^2 term.

9x^(2)+12x+4=0

a = 9 ; b = 12; c = 4;

discriminant = Δ = b^(2) - 4ac

             

Δ = 12^(2) - (4*9*4) = 144 - 144 = 0

roots of quadratic equations are [ (-b ± √Δ)/ 2a)]

let roots of eqation are x1 & x2

As discriminant is zero so, x1=x2

x1 = x2 = -b/2a = - 12/(2*9) = -2/3

learn more about quadratic equations here brainly.com/question/1214333

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Answer:

hello :

9x^2+12x+4=0

a = 9   b = 12    c = 4

the discriminant  Δ = b² - 4ac = 12² - 4(9) (4   ) =144 -  144 = 0

x1 = x2 = - b/2a = -12/18 = - 2/3

  the real root is : - 2/3