Answer:
Step-by-step explanation:
Let v be the speed after the collision of both the cars.
Now, momentum is given by: mass × velocity, then by equating the total momentum before and after the collision of the two cars, we get
⇒
⇒
⇒
Thus, they are moving at the velocity of
Answer:
0.5 m/s
Step-by-step explanation:
A 500 g model train car traveling at 0.8 m/s collides with a 300 g stationary car.
Initial velocity of train,
Initial velocity of car,
Mass of train,
Mass of car,
The cars hook up and move off down the track together.
Let the final velocity of car and train,
Using conservation of momentum,
Momentum before collision = Momentum after collision
Hence, After collision they will going with 0.5 m/s
x= -3, -1
X= 3,1
x=3, -1
Answer:
{-1, 3}
Step-by-step explanation:
Please use " ^ " to denote exponentiation: f(x) = x^2 - 2x - 3.
To find the zeros of this quadratic, set it equal to zero first:
f(x) = x^2 - 2x - 3 = 0.
Now factor this result: (x - 3)(x + 1) = 0.
The zeros are {-1, 3}