MATHEMATICS MIDDLE SCHOOL

What is the value of y?

6(5 + 3) = 6 • 5 + 6 • y

Answers

Answer 1
Answer: 6(5+3)=6\cdot5+6\cdot y\n\n6(8)=30+6y\n\n48=30+6y\ \ \ \ |subtract\ 30\ from\ both\ sides\n\n18=6y\ \ \ \ |divide\ both\ sides\ by\ 6\n\n3=y\n\n\huge\boxed{y=3}
Answer 2
Answer:
6(5+3)=(6)(5)+6y

Simplify

6(5+3)=(6)(5)+6y

48=30+6y

48=6y+30

Flip the equation.

6y+30=48

Subtract 30 from both sides.

6y+30−30=48−30

6y=18

Divide both sides by 6.

6y / 6 = 18/ 6

y=3

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two unidentified flying discs are detected by a receiver, the angle of elevation from the receiver to each disc is 38.48 degrees. The discs are hovering at a direct distance of 826metres and 1.296km from the receiver. Find the difference in height between the two flying discs.

Answers

Answer:

292.45 m

Step-by-step explanation:

Both disk are at an angle of 38.48°

From the image below we calculate as,

For disk B, direct distance is 1.296 km from receiver = 1296 m

Vertical height from ground will be = 1296 x sin38.48 = 806.42 m

For disk A, direct distance is 826 m from receiver

Verival height above ground = 826 x sin38.48 = 513.97 m

Difference in height between disks is 806.42 - 513.97 = 292.45 m

What is the name of this shape

Answers

Parallelogram I believe
A rectangle....unless it isn't a photo taken from a weird angle....but thats a rectangle.

Movie tickets cost $7 for students and $9 for adults. A group of 8 people spent $66 on movie tickets. How many adult tickets were bought?

Answers

It would be 5 adults.

Solve for h.
P=mgh
Answer choices:
H=P-mg
H=pg/m
H=p/mg
H=P+mg

Answers

P=mgh
p/mg=h

the answer is:
H=p/mg

Answer:

The answer is H = p/mg.

Step-by-step explanation:

Give the variables actual values, and then solve. Let's say:

H = 4

G = 3

M = 2

The equation P = mgh tells us to multiply m x g x h. 3 x 2 x 4 = 24, so P = 24.

Now our values are:

P = 24

H = 4

G = 3

M = 2

So now we have to find which equation is equal to 4, or the value we have substituted for H.

So let's test the answer choices out.

H = P - mg. This would say that 4 = 24 - 2 x 3. 2 x 3 = 6, and 24 - 6 is 18. 18 is not equal to 4, so H = P - mg is not the correct answer.

H = pg/m. This would say that 4 = 24 x 3 divided by 2. 24 x 3 is 72, and 72 divided by 2 is 36. 36 is not equal to 4, so H = pg/m is not the correct answer.

H = P + mg. This would say that 4 = 24 + 2 x 3. 2 x 3 is 6, and 24 + 6 is 30. 30 is not equal to 4, so H = P + mg is not the correct answer.

H = p/mg. This would say that 4 = 24 divided by 2 x 3. 2 x 3 is 6, and 24 divided by 6 is 4. 4 is equal to 4, so H = p/mg is the correct answer.

This formula of substituting the variables for values can work for any value. Just do yourself a favor and make it easy for yourself, by not choosing values like 13045. That's just a waste of time.

a photo masured 15cm by 10cm andbis put in a frame that measures 25cm by 20cm calculate the are of the space between the photograph and the frame

Answers

The frame is 25x20cm, meaning hat it has an area of 500. The photo is 15x10, meaning it has an area of 150. Therefore, if you subtract the areas (500-150) you get an area between the photograph of 350 cm squared.

A 2000 gram sample of radioactivematter will completely decay (be
undetectable) in 20 hours. There
exists a set of ordered pairs (t, m),
where t is the amount of time in hours
that the substance has been decaying,
and m is the mass in grams that has
decayed.
If t > 0, what is the range of m?

Answers

Answer:

The range is 0 < m < 2000 when t > 0

Step-by-step explanation:

* Lets explain how to solve the problem

- The exponential function is f(x)= a(b)^(x) , where

  a is the initial amount and b is the growth factor

- If b > 1, then it is exponential growth function

- If 0 < b < 1, then it is exponential decay function

* Lets solve the problem

- A 2000 gram sample of radioactive  matter will completely decay

 (be  undetectable) in 20 hours

- There is a set of ordered pairs (t , m) exists, where t is the amount

  of time in hours  that the substance has been decaying and m is

  the mass in grams that has  decayed

∵ We can represent this situation by an exponential decay function

∴ m(t)= 2000(b)^(t) , where b is the growth factor which is

  greater than zero and less than 1 , t is the lime in hours and

  m(t) is the mass of the substance in gram

- In any function the domain is the value of x and the range is

 the value of y

∵ In the function the domain is t and the range is m

∵ When t = 0 then m = 2000 ⇒ initial amount

∵ When t = 20 then m will be closed to zero

∴ The domain of the function is 0 < t < 20

∴ The range of the function is 0 < m < 2000

* The range is 0 < m < 2000 when t > 0
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