A school debate team has 4 girls and 6 boys. A total of 4 of the team members will be chosen to participate in the district debate. What is the probability that 2 girls and 2 boys will be selected?

Hey!

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Question #1:

= 6n^2 - 2n - 3 + 5n^2 - 9n - 6

= 6n^2 + (-2n) + (-3) + 5n^2 + (-9n) + (-6)

= (6n^2 + 5n^2) + (-2n + -9n) + (-3 + -6)

= (11n^2) + (-11n) + (-9)

Answer: 11n² + (-11n) + (-9)

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Question #2:

= 8c^2 - c + 3 + 2c^2 - c + 2

= 8c^2 + (-c) + 3 + 2c^2 + (-c) + 2

= (8c^2 + 2c^2) + (-c + -c) + (3 + 2)

= (10c^2) + (-2c) + (5)

Answer: 10c² + (-2c) + 5

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Hope This Helped! Good Luck!

Answer:

1. 11n^2-11n-9

2. 10c^2-2c+5

Step-by-step explanation:

1. 6n^2+5n^2 = 11n^2

-2n-9n = -11n

-3-6=-9

2. 8c^2+2c^2 = 10c^2

-c-c= -2c

3+2=5

Answer: 6 feet

Step-by-step explanation:

Hi, to answer this question we have to apply the next formula:

Volume of a cone= (1/3) π radius² height

Replacing with the values given and solving for r:

36π = (1/3) π r² 12

36π/ [(1/3) π 12]= r²  

9 = r²  

√9 =r

3 ft = r

Since:

Diameter = 2 x radius

Substituting r=3  

D = 2x 3

D = 6 feet

Feel free to ask for more if needed or if you did not understand something.