Why are the flat surfaces on a rectangular prism called faces

Answers

Answer 1

Answer:

The flat surfaceson a rectangular prism are called faces because they form the exterior of the rectangularprism, and they are the only parts of the prism.

What is Three dimensional shape?

a three dimensional shape can be defined as a solid figure or an object or shape that has three dimensions—length, width, and height.

A rectangularprism is a polyhedron with two congruent and parallel bases.

Rectangular prism is also called a cuboid

The flat surfaces on a rectangular prism are called faces because they form the exterior of the rectangular prism, and they are the only parts of the prism that can be seen from the outside.

Each face has two dimensions (length and width) and all six faces together form the rectangular prism's shape.

Hence, the flat surfaces on a rectangularprism are called faces because they form the exterior of the rectangular prism, and they are the only parts of the prism.

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Answer 2

Answer: Because they act like a face that provides recognition to the shape.

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Please help on this! I will mark brainliest if right!

Two fractions between 0.75 and 0.79?

Answers

There are infinite amount of fractions between two numbers.
Some in between 0.75 and 0.79 are:
0.76, 0.77, and 0.78

Hope this helps :)

What is the independent variable for the graph?

Answers

time is the independent variable

Can someone please explain to me what should I do? Thank you!

Answers

It would be B. 2/5
Count the tick marks by 10th so at the dot it's -4/10 which simplify to -2/5. And the absolute value of -2/5 is 2/5.

All you have to do is make the point positive

In rectangle $ABCD$, $P$ is a point on $BC$ so that $\angle APD=90^{\circ}$. $TS$ is perpendicular to $BC$ with $BP=PT$, as shown. $PD$ intersects $TS$ at $Q$. Point $R$ is on $CD$ such that $RA$ passes through $Q$. In $\triangle PQA$, $PA=20$, $AQ=25$ and $QP=15$. Find $SD$. (Express your answer as a common fraction.)

Answers

Answer:

$(28)/(3)$

Step-by-step explanation:

Given information: ABCD is a rectangle, $\angle APD=90^(\circ)$ , PA=20, AQ=25 and QP=15.

In a right angled triangle

$hypotenuse^2=base^2+perpendicular^2$

In triangle ABP, AB = 16 and AP = 20. Using Pythagoras theorem we get

$(AB)^2 + (BP)^2 = (AP)^2$

$16^2 + (BP)^2 = 20^2$

$(BP)^2 = 20^2-16^2$

$BP^2 = 144$

$BP = 12$

Since BP = PT, therefore PT = 12.

$AS = BP + PT = 12 + 12 = 24$

AQS is a right angled triangle and AQ = 25. Use Pythagoras theorem in triangle AQS.

$(AS)^2 + (SQ)^2 = (AQ)^2$

$24^2 + (SQ)^2 = 25^2$

$SQ = 7$

Triangle PQT is a right triangle. Use Pythagoras theorem in triangle PQT.

$(PT)^2 + (QT)^2 = (PQ)^2$

$12^2 + (QT)^2 = 15^2$

$QT = 9$

In triangle PTQ and DSQ,

$\angle TQP=\angle SQD$ (Vertical angles)

$\angle PTQ=\angle DSQ$ (Right angles)

Triangle PTQ is similar to triangle DSQ by AA property of similarity.

Corresponding parts of similar triangles are proportional.

$(PT)/(QT)=(SD)/(SQ)$

$(12)/(9)=(SD)/(7)$

On cross multiplication we get

$9SD=12* 7$

$9SD=84$

Divide both sides by 9.

$SD=(84)/(9)$

$SD=(28)/(3)$

Therefore, $SD=(28)/(3)$ .

Write
as a decimal.
What is 3/5 as a decimal

Answers

Answer is provided in the image attached.

0.6 is the answer!!!!!!!!!!!!!!!!

1.A farmer has 4000 metres of fencing, he wants to enclose a rectangular field that borders on a river. If the farmer doesn't fence the side along theriver, what is the largest area he can inclose? The area of the garden is give by:

A(x)=4000x-2x^2 (^2=squared)

2. A texas based company called hamilton's wares sells baseball bats at a fixed price, c. A field researcher has calculated that the profit the company makes selling the bats a price c can be represented by the following equation:

p(c)=1/5c^3-51/2c^2+110c

What price should they sell their bats at to make the most money.

Please show full working out for both questions, ^3 means to the power of 3.

Answers

I send you the answers:

1)
Answer: the area is 2,000,000 m²

2)
The price that they should sell your bats is $2,214

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Solve Two Step Eqautions1. 5n+8=43 2. 8w-5=57 3. f/5 - 22 = -25 4. y/6 - 7 =4 5. g/3 + 11 = 25 6. -4p + 19 = 11

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