To the nearest tenth of a percent, what is 8/13 written as a percent? Answers: A. 0.6%   B. 6.2%   C. 61.5%   D. 615.4%

Answers

Answer 1
Answer: the answer to your problem is C.


Answer 2
Answer: A. 0.6% is the answer to 8/13

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Answers

DjhdgaushsyshahshahjziskskqjshfgfshaisjzbahjJsjahshshdhdhhdhdhdh just doing to for points lol lmaoo

Please help solve 0.6x =3.2

Answers

Answer: x=5.33

0.6x=3.2
divide both sides by 0.6
x=5.3333 or 5 1/3
Ok so wld have to see how many times .6 can go into 3.2
divide 3.2 by .6 which wld equal...5 and 1 third or...
5.33333333333333333333333

BRAINILIEST!!!!!What is the quotient
7
-7
-343
343

Answers

The quotient for the question is: -343

The answer would be option C. -343

Hope this helps


-Maranda

What is the distance from (23. 5) 0 (23. -12)?

Answers

The distance between (23,5) and (23,-12) is 17 units.

Because the x values are equal then this makes this problem much easier. Since y value 5 and y value -12 are in different quadrants then you would add them together (because one value is positive and one is negative). You need to add 5 and the absolute value of -12 which is 12. Adding 5 and 12 and you would get 17.

Complete the equation of the line through (-9,-7) and (-6,-3)

Answers

The equation of the line through (-9, -7) and (-6, -3) is y+3=(4)/(3)(x+6)

Solution:

Given, two points are (-9, -7) and (-6, -3)

We have to find that a line that passes through the given two points.

First let us find the slope of the line that passes through given two points.

The slope of the line "m" is given as:

\mathrm{m}=(y_(2)-y_(1))/(x_(2)-x_(1))

\text { where, }\left(x_(1), y_(1)\right) \text { and }\left(x_(2), y_(2)\right) \text { are two points on line. }

So slope of our line =(-3-(-7))/(-6-(-9))=(-3+7)/(-6+9)=(4)/(3)

Now, let us find the line equation using point slope form:

\mathrm{y}-\mathrm{y}_(1)=\mathrm{m}\left(\mathrm{x}-\mathrm{x}_(1)\right) \text { where } \mathrm{m} \text { is slope and }\left(\mathrm{x}_(1), \mathrm{y}_(1)\right) \text { is point on the line. }

By substituting the values we get,

\text { Then, line equation } \rightarrow y-(-3)=(4)/(3)(x-(-6))

y+3=(4)/(3)(x+6)

Hence, the line equation is y+3=(4)/(3)(x+6)

Value of the expression 3[5.4+6(2.3)

Answers

your answer will be 57.6