Divide the fractions and simplify the answer . 1/2 ÷ 5/8

Answers

Answer 1

Answer: Dividing fractions is equivalent to taking the reciprocal of the second and multiplying them. In this case, we have 1/2*8/5=8/10=4/5.

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If it takes Mark twice as long to earn $6.00 as it takes Carl to earn $4.00, what is theratio of Mark’s pay per hour to Carl’s pay per hour?

Answers

The ratio of Mark’s pay per hour to Carl’s pay per hour is 3:4 given that Mark takes twice as long as to earn $6.00 as it takes Carl to earn $4.00. This can be obtained by dividing their hourly wages.

What is the required ratio?

Given that, Mark takes twice as long as to earn $6.00 as it takes Carl to earn $4.00.

(Time taken for Mark to earn $6)=2×(Time taken for Carl to earn $4)

Time taken for Mark to earn $3 = Time taken for Carl to earn $4

This means that Mark takes the same amount of time to earn $3.00 as Carl earn $4.00.

Thus the ratio of Mark’s pay per hour to Carl’s pay per hour, 3/4 = 3:4

Learn more about ratio here:

brainly.com/question/24559300

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If it takes Mark twice as long to make $6.00 than Carl making $4.00, this means Mark made $3.00 in the time it took Carl to make $4.00.
So the ratio is $3.00 to $4.00, or 3/4.

Follow the steps in purple to evaluate:4
+
9
To add or subtract fractions, their denominators
must be the same. We can get a common
denominator by multiplying the second fraction
by 3/3.
6
-
(-}).
What number belongs in the green box?
Enter

Answers

I think it is 3 but I’m not 100%

If a coin is flipped 75 times, in how many ways could there be exactly two tails?

Answers

Answer:

2775 ways

Step-by-step explanation:

We have been given the case to choose exactly two tails when flipped 75 times means $^(75)C_2$

Since, $^nC_r$ is equal to $(n!)/(r!\cdot(n-r)!)$

Here n =75, r=2 substituting the values we will get

$(75!)/(2!(75-2)!)$

$n!=n\cdot (n-1)\cdot (n-2).....1$

After simplification we will get $(75\cdot 74\cdot 73!)/(2!\cdot73!)$

Cancel out the common term that is 73! we will get

after more simplification we will get $(75\cdot 74\cdot)/(2!)$

Finally, we will get $(75\cdot 74\cdot)/(2)=75\cdot37=2775$

I think the answer is 2774 but dont quote me on it

Four people in a room. Each shakes hands with each of the others once. How many handshakes are there? 6
10
12
16
22

Answers

The correct answer is 6.

The clearest way to determine this is by creating a table of possible hand shaking. If we label the people A-D, the following are the ways they can be combined:
AB
AC
AD
BC
BD
CD

There are no other combinations.

There are 6 handshakes betweenfour people in the room.

Further explanation

The probability of an event is defined as the possibility of an event occurring against sample space.

$\large { \boxed {P(A) = \frac{\text{Number of Favorable Outcomes to A}}{\text {Total Number of Outcomes}} } }$

Permutation ( Arrangement )

Permutation is the number of ways to arrange objects.

$\large {\boxed {^nP_r = (n!)/((n - r)!) } }$

Combination ( Selection )

Combination is the number of ways to select objects.

$\large {\boxed {^nC_r = (n!)/(r! (n - r)!) } }$

Let us tackle the problem.

This problem is about Combination.

If there are 4 people in a room , then the number of handshaking between 2 people is analogy as selecting 2 people from 4 people available. We will use combination formula in this problem.

$^4C_2 = (4!)/(2! (4-2)!)$