Answer:
Hope it helps you............
To find the remaining area of the paperboard, calculate the area of the rectangle, subtract the area of the semicircle. The area of the rectangle is 336 square inches, and the area of the semicircle is 32π square inches. The remaining area is approximately 236.05 square inches.
To answer this question, we first need to calculate the area of the entire paperboard, and then calculate the area of the semi-circle that was cut out. We then subtract the area of the semi-circle from the area of the paperboard to get the remaining area.
The area of a rectangle is calculated by multiplying its length by its width. For the paperboard, we find the area by multiplying 21 inches (length) by 16 inches (width), which gives us 336 square inches.
Next, we have to calculate the area of the semi-circle that was cut out. Assuming the cut was made along the width of the paperboard, the diameter of the semi-circle would be 16 inches. The radius, therefore, is 8 inches. The area of a circle is given by the formula πr², where r is the radius. For a semi-circle, we simply take half of this. This gives us an area of half of π(8)² = 32π square inches.
So, to find the remaining area of the paperboard, we subtract the area of the semi-circle from the area of the rectangle: 336 square inches - 32π square inches = approximately 236.05 square inches.
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Answer:
y = -15x - 6
Step-by-step explanation:
To rewrite the function 5x + 1/3y = -2 in slope-intercept form, we first isolate 'y' and then multiply by 3 to get y = -15x -6.
The given linear function is 5x + 1/3y = -2. To rewrite this in slope-intercept form, i.e., y = mx + b, where m is the slope and b is the y-intercept, we apply some algebraic manipulations:
The process we just followed is called converting a linear equation to slope-intercept form.
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y ≥ x - 2 and y ≤ 2x - 3
y ≥ 3x - 2 and y ≤ x + 3
y ≤ 3x - 2 and y ≥ x + 3
The graph shows the solution for the inequalities y ≥ 3x - 2 and y ≤ x + 3.
The inequalities can be found by substituting the coordinates of a point within the shaded area in both inequalities and seeing if they are satisfied.
The options are given.
Let us take the options one by one:
Now, substitute (0,0) in the inequalities:
0 ≥ 2 and 0 ≤ 3
This is not true.
Now, substitute (0,0) in the inequalities:
0 ≥ - 2 and 0 ≤ - 3
This is not true.
Now, substitute (0,0) in the inequalities:
0 ≥ - 2 and 0 ≤ 3
This is true.
Now, substitute (0,0) in the inequalities:
0 ≥ - 2 and 0 ≤ - 3
This is not true.
Therefore, we have found that the inequalities are y ≥ 3x - 2 and y ≤ x + 3. The correct answer is option C.
Learn more about inequalities here: brainly.com/question/24372553
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Answer:
and
Step-by-step explanation:
Blue:
The inequality for the blue line is
Yellow
The inequality for the yellow line is
This means that the correct answer is the third option,
and