I am a 3-digit number that is even. My hundreds and ones digits are the same and have a sum of 8. My tens digit is 2 less than my ones digit. What number am I ?
Answers
The number has 3 digits.
Even numbers end with 0, 2, 4, 6, or 8. (Obviously)
The hundreds digit and ones digit are the same.
First number in a 3 digit number is the hundreds, and the last number is the ones.
So, both of those two digits are the same and has to equal 8.
Well,
The hundreds place and the ones place are 4.
The tens digit is the middle number in a 3-digit number.
It is two numbers less than the ones digit.
The number is 424.
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b . An 18 ct gold chain contains four grams of pure gold. How much other metal does it contain? c. What is the ratio of gold to other metals in 14 ct gold?
d. What is the ratio of gold to other metals in 9 ct gold?
Answers
To calculate the mass of other metals in each scenario, we need to use the given ratios.
Given:
- Pure gold is 24 carats (ct).
- 18 carat gold is an alloy of gold and other metals in the ratio 18:6 (18/24 parts pure gold and 6/24 other metals).
a. A jeweller makes an 18 ct gold alloy using three grams of pure gold. What mass of other metals does she add?
First, let's find the mass of other metals in the 18 ct gold alloy.
18 ct gold contains 18/24 parts pure gold and 6/24 parts other metals. So, if the jeweller uses 3 grams of pure gold, the amount of other metals in the alloy can be calculated as follows:
Mass of other metals = (6/24) * 3 grams
Mass of other metals = (1/4) * 3 grams
Mass of other metals = 3/4 grams
b. An 18 ct gold chain contains four grams of pure gold. How much other metal does it contain?
Similarly, for the 18 ct gold chain containing 4 grams of pure gold:
Mass of other metals = (6/24) * 4 grams
Mass of other metals = (1/4) * 4 grams
Mass of other metals = 4/4 grams
Mass of other metals = 1 gram
c. What is the ratio of gold to other metals in 14 ct gold?
For 14 ct gold, the ratio of gold to other metals is 14:10 (since 14 + 10 = 24, and gold is 14 out of 24 parts, while other metals are 10 out of 24 parts).
d. What is the ratio of gold to other metals in 9 ct gold?
For 9 ct gold, the ratio of gold to other metals is 9:15 (since 9 + 15 = 24, and gold is 9 out of 24 parts, while other metals are 15 out of 24 parts).
Answers
the labor cost is
so the labor cost is 32% of the revenue.
Pleas help :)
Answers
y = ⁸/₉x - 3¹/₃
The slope is ⁸/₉.
Y - Intercept
y = ⁸/₉x - 3¹/₃
y = ⁸/₉(0) - 3¹/₃
y = 0 - 3¹/₃
y = -3¹/₃
The y-intercept is -3¹/₃
The answer is C.
Answer:
C. The slope is 8⁄9 and the y-intercept is -3⅓ [or -10⁄3].
Step-by-step explanation:
According to the Slope-Intercept Formula, y=mx+b,bis your y-intercept, so that is a giveaway. Now, your rateofchange[slope], which is represented by m,is the coefficient, meaning the term in front of x,so that is also a giveaway.
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B.(37.68 in2)
C.(1808.64 in2)
D.(452.16 in2)
Answers
Circumference = diameter x pi
Find the diameter:
75.36 = diameter x pi
Divide both sides by pi:
Diameter = 75.36/3.14 = 24 inches.
Area = pi x r^2
R = 1/2 diameter = 12
Area = 3.14 x 12^2
Area = 452.16 in^2
The answer is D.
1.One and one-eighth
2.One and three-eighths
3.Two and one-eighth
4.Two and three-eighths
Answers
Answer:
The Answer is One and Three Eighths
Step-by-step explanation:
Good Luck! Sorry this Answers late but other people can use it :)
Answer:
I dont get what you are asking can you put more detail for what you want the answer to be please
Step-by-step explanation:
b. 110
c. 32
4. 70
Answers
The value of x is 16. The correct option is A.
What are vertical angles?
Each of the pairs of opposite angles made by two intersecting lines is called a vertical angle.
Given that the measure of two vertical angles is 8x - 18 and 6x + 14. Since the two angles are vertical angles, therefore, will measure the same. Thus, we can write the measure of the two angles as,
8x - 18 = 6x + 14
Bring liketerms on the same side of the equation,
8x - 6x = 18 + 14
Simplify both sides of the equation,
2x = 32
x = 32/2
x = 16
Hence, the value of x is 16.
Learn more about Vertical Angles here:
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