(2) low temperature and high pressure
(3) high temperature and low pressure
(4) high temperature and high pressure
evaporating a liquid
cooling a solid
cooling a liquid
The answer is 3/2 the original pressure. The concept behind this is the ideal gas law wherein it states that Pressure (P) times volume(V) is equal to number of moles (n) times ideal gas constant (R ) times temperature (T). Since you’re trying to calculate for the pressure you use P=nRT/V. Input 3 to Temperature and 2 to volume. You’ll get a pressure of 3/2 which is 3/2 times the original pressure.
Answer: ethylene glycol (molar mass = 62.07 g/mol)
Explanation:
Depression in freezing point :
Formula used for lowering in freezing point is,
or,
where,
= change in freezing point
= freezing point constant=
m = molality
Given mass of solute = 0.807 g
Molar mass of solute=? g/mol
weight of solvent in kg= 11.6 g=0.0116 kg
Thus the solute is ethylene glycol which has same molecular mass as calculated, i.e 62.07 g/mol.