A man with mass 81 kg lies on the floor. What is the normal force on the man?A. 855 N
B. 794 N
C. 713 N
D. 820 N

Answers

Answer 1

Answer: $F=m\cdot g\ \ \ \ \wedge\ \ \ \ g\approx9.8\ m/s^2\n \nF\approx81\ kg\cdot9.8\ m/s^2=793.8\ (kg\cdot m)/(s^2) \approx794\ N\ \ \ \Rightarrow\ \ \ Ans.\ B$

Answer 2

Answer: Forces come in pairs, so the force of gravity (9.8 N) with the mans weight (794N) on the earth is counteracted with the normal force ( the force of the earth back on the man) which is the same

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Which is bigger 78%, 0.8

How many km is 525 meter

Answers

Hello,

The answer is 0.525 km

Remember, there are 1000 m in a kilometer.

Thanks for using brainly :)

Find the common ratio for the following sequence. 27, 9, 3, 1, .

Answers

27/9 = 3

9/3= 3

3/1 = 3

Answer: 3

Find the slope of each line that passes through each pair of points The points (3, 5) and (-2, 10) lie on a line. The points P (5,-7), Q (-2,-7) lie on a straight line

Answers

Answer:

m = -1
m = 0

Step-by-step explanation:

$\mathrm{Slope}=(y_2-y_1)/(x_2-x_1)\n\n\left(x_1,\:y_1\right)=\left(3,\:5\right),\:\left(x_2,\:y_2\right)=\left(-2,\:10\right)\n\nm=(10-5)/(-2-3)\n\nm=(5)/(-5)\n\nsimplify\n\nm=-1$

$\mathrm{Slope}=(y_2-y_1)/(x_2-x_1)\n\n\left(x_1,\:y_1\right)=\left(5,\:-7\right),\:\n\left(x_2,\:y_2\right)=\left(-2,\:-7\right)\n\nm=(-7-\left(-7\right))/(-2-5)\n\nm=(-7+7)/(-7) \n\nm = (0)/(7)\n\nSimplify\n\nm =0$

If pqr = 1 , rst = 0 , and spr = 0, which of the following must be zero?A. P
B. Q
C. R
D. S
E. T

Answers

P,Q,R can't be 0, because their product is nonzero. Either of S and T could be 0, but the third one only works if S is 0.

Solve each equation by taking square roots

-3x^2=-105

Answers

$-3x^2=-105$

$x^2= (-105)/(-3)$ $Divide \ both \ sides \ by \ -3$

$x^2= (105)/(3)$

$x^2=35$

$x=+ √(35)$ $Take \ the \ square \ root \ of \ both \ sides$

$x = 5.916$ $Solution$

Given the following functions f(x) and g(x), solve (f + g)(3) and select the correct answer below:f(x) = 6x + 3
g(x) = x − 7
4
17
25
31