Who can tell this answer

Answers

Answer 1

Answer: $(16*16*16)+(10*8.5*16)=4096+1360=5456(in^(3) )$

Answer 2

Answer: here you go, hope this helps

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HELP PLEASE I REALLY NEED HELP PLEASE HELP!!

how many minutes is it before 12 noon if 20 minutes ago it was three times as many minutes after 9 am

Answers

First, change everything into minutes.
12 noon is 12 by 60 which = 720 minutes.
9am is 9 by 12 which = 540 minutes.
X is now your number of minutes before noon.So noon - x is the next step:
720 - x
20 minutes ago it was 720 - x - 20
720 - x - 20= 540 + 3x (3x because you're looking for 3 times as many minutes)
720 - 20 - 540=4x (you combine all the like numbers and variables)
160 = 4x
160/4= x
40 = x
Your answer is 40 minutes

Can some explain me how to find the answers

Answers

(a) r = the weight of Rajesh's package and m = the weight of Mohib's package:

r = 2m + 3
r + m = 15

(b) The easiest way to solve this equation would be to use substitution. The first equation says that r is equal to "2m + 3", so we can plug 2m + 3 in for the r in the second equation, and then solve for m:

$r+m=15\(2m+3)+m=15\3m+3=15\3m=12\m=4$

Now that we have m, we can plug it into one of the equations to find r:

$r=2m+3\r=2(4)+3\r=8+3\r=11$

So, the weight of Rajesh's package is 11 pounds, and the weight of Mohib's package is 4 pounds. This makes sense because both of these add up to 15 and Rajesh's package is three more than two times the weight of Mohib's package, as described in the question.

(c) Mohib's graph is the correct graph because it intersects at the correct point (4 on the Mohib axis and 11 on the Rajesh axis). The other graph shows the intersection of the two lines at the wrong point, giving the wrong weights of the two packages.

what textbook and pg # is this? I wanna be able to practice

What are the first six nonzero multiples 5

Answers

5*1 = 5
5*3 = 15
5*5 = 25
5*7 = 35
5*9 = 45
5*11 = 55
None of them involve 0's

5,15,25,35,45,55,65 is that is far as you need it

at 4:40 pm the thermometer outside of Yasmin's window read 40°c It had risen 8° betwen noon and 4:30 pm and 5° bertwen 7am and noon . What was the temperature at 7am?

Answers

at 4:30 the temperature is 40 degrees, and this temperature is 8 degrees more than what is was at noon. so we subtract 8 from 40 to get 32 degrees at noon. then we subtract 5 from 32 to get the temperature at 7 am. The temperature at 7 am is 27 degrees

....????? plzz helllpppp

Answers

Answer:

$\cos 60= (1)/(2)$

$\tan 60 = √(3)$

Step-by-step explanation:

See the diagram given with the question first.

Here we are given a right triangle with two angles other than the right angle are 60° and 30°.

The length of the side opposite to 30° is 4 and the side opposite to 60° is 4√3 and automatically the length of the hypotenuse is 8.

Now, $\cos 60= (Base)/(Hypotenuse) = (4)/(8) = (1)/(2)$

Again. $\tan 60 = (Perpendicular)/(Base) =(4√(3) )/(4) =√(3)$

(Answer)

Find the value of x.
A) 71
B) 72
C) 73
D) 75

Answers

146° + (-39 +x)° = 180°

Subtract 146° on both sides.

(-39 +x)° = 180° - 146°

(-39 +x)° = 34°

(x - 39)° = 34°

Add 39° on both sides

x = 34° + 39°

x = 73°

Your final answer is C) 73.

146 - 39 + x = 180

107 + x = 180

x = 73

Your answer is C) 73.