Calculate the discriminant.x2 – 2x + 4 = 0

  20
      12
    –12
      0

Answers

Answer 1

Answer: $x^2 - 2x + 4 = 0 \n \n\Delta =b^2-4ac =(-2)^2-4*1*4=4-16=-12$

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Find the product. (a-6)^2=

Answers

Answer:

a^2-12a+36

Step-by-step explanation:

;)

If a rectangle measures 20 meters by 48 meters, what is the length, of the diagonal of the rectangle? Can you help me with this one ?

Answers

$the \ width \ of \ the \ rectangle : \ w=20 \ m \n \n the \ length \ of \ the \ rectangle : \ l=48 \m \n \n Diagonal : \ √(w^2 + l^2)\n \nD =√(20^2 + 48^2) \n \nD=√(400+2304)=√(2704)= 52 \ m$

Evaluate and simplify cos 2pi/3. The options for answers are in the picture attachment, but I have NO idea how to get any of them? Please, Any help is appreciated (:

Answers

when pi is inside the trigonometric function you can subs. it by 180 degree
so cos(2*180/3) = cos(120) = -0.5

Help and solve for x
2(2x+6)

Answers

Answer:

x = 3

Step-by-step explanation:

2(2x + 6)

4x + 12

4/4 = 1

12/4 = 3

x = 3

Hopefully this helps you :)

pls mark brainlest ;)

Consider f(x)=2|x|What is the rate of change over the interval 0≤x≤4?

How is the rate of change over this interval related to the form of the function?

Answers

Answer:

Please check the explanation.

Step-by-step explanation:

As we know that the average rate of change of f(x) in the closed

interval [a, b] is

$(f\left(b\right)-f\left(a\right))/(b-a)$

Given the interval [a, b] = [0, 4]

$f(x)=2|x|$

$f(b)=f(2)=2\cdot \:4$ ∵ $\mathrm{Apply\:absolute\:rule}:\quad \left|a\right|=a,\:a\ge 0$

$= 8$

$f(x)=2|x|$

$f(a)=f(0)=2\cdot \:0$ ∵ $\mathrm{Apply\:absolute\:rule}:\quad \left|a\right|=a,\:a\ge 0$

$= 0$

so the average rate of change :

$(f\left(b\right)-f\left(a\right))/(b-a)=(8-0)/(4-0)$

$=(8)/(4)$

$= 2$

We know that a rate of change basically indicates how an output quantity changes relative to the change in the input quantity. Here, it is clear the value of y increase with the increase of input.

What is the lower quartile of the data set 4,10,10,14,4,25,15,22,16,10