MATHEMATICS HIGH SCHOOL

Adrianne invested $2000 in an account at a 3.5% interest rate compounded annually. She madeno deposits or withdrawals on the account for 4 years. Determine, to the nearest dollar, the
balance in the account after the 4 years.

Answers

Answer 1
Answer:


With the information given, you can make the expression 2000*3.5%*4, because the interest in a year is 3.5% of 2000 and it goes for four years.

Change 3.5% to 0.035:

2000*0.035*4

Multiply:

70*4

280

To find the total balance, add 2,000 to the amount of interest earned, 280.

2000+280=2280.

Therefore, after the 4 years pass, the account balance is $2280.

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Answers

Answer:

give each friend 2 origami figures

Step-by-step explanation:

1+4=5, 2+5=12, 3+6=21, 8+11?

Answers

The answer is 96.
Solution:
1+4(5) = 5
2+5(7) = 12(5+7)
3+6(9) = 21(12+9)
4+7(11) = 32(21+11)
5+8(13) = 45(32+13)
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7+10(17) = 77(60+17)
8+11(19) = 96(77+19).

Which of the following statistical measures is least appropriate for describing the data set shown below? 1, 5, 5, 5, 6, 6.5, 7, 30

mean
mode
median

Answers

arrange data set in ascending order

1, 5, 5, 5, 5, 6, 6, 7, 30

mean = 7.78
mode = 5
median = 5

The least appropriate measure for describing the data set is MEAN. This is because it is affected by the outlier, 30.

Answer:

Short answer shorter, its A: mean

Step-by-step explanation:

Product of 5 and the quantity 3 plus z

Answers


That expression could be written as

                                           5 (3 + z) .
I think written out it would be 5(3+z), so the product would be 5z+15 because you distribute the 5 to the three and z. hope this helps!

Challenge The price of Stock A at 9 am was $14.11. Since then the price has been increasing atthe rate of $0.08 each hour. At noon the price of Stock B was $14.86. It begins to decrease at the
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In about

Answers

it would be 6 be cause 14 -8 is 6

Solve each equation with quadratic formula.2v2+12v-27=9v

Answers

2v^2+12v-27=9v\ \ \ \ /-9v\n\n2v^2+3v-27=0\n\na=2;\ b=3;\ c=-27\n\n\Delta=b^2-4ac\n\n\Delta=3^2-4\cdot2\cdot(-27)=9+216=225\n\nv_1=(-b-\sqrt\Delta)/(2a);\ v_2=(-b+\sqrt\Delta)/(2a)\n\nv_1=(-3-√(225))/(2\cdot2)=(-3-15)/(4)=(-18)/(4)=-4(1)/(2)\n\nv_2=(-3+15)/(2\cdot2)=(12)/(4)=3

2v^2+3v-27=0\n\n2(v+4(1)/(2))(v-3)=0\n\nAnswer:v=-4(1)/(2)\ \vee\ v=3.
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