A box has 6 beads of the same size, but all are different colors. Tania draws a bead randomly from the box, notes its color, and then puts the bead back in the box. She repeats this 3 times. What is the probability that Tania would pick a yellow bead on the first draw, then a blue bead, and finally a yellow bead again?1/216

1/36

1/6

1/2

Answers

Answer 1
Answer:

The probability that Tania would pick a yellow bead on the first draw, then a blue bead, and finally a yellow bead again is 1/216.

What is Probability?

The probability helps us to know the chances of an event occurring.

\rm{Probability=(Desired\ Outcomes)/(Total\ Number\ of\ outcomes\ possible)

As it is given that the box has 6 beads of the same size, but all are different colours. therefore, the probability of any bead being selected is 1/6.

Now, we know that when Tania picks a bead she puts it back in the box, therefore, the sample size of the box will be the same and also the probability of each bead will be the same as well.

Further, the probability that Tania would pick a yellow bead on the first draw, then a blue bead, and finally a yellow bead again can be written as,

\rm Probability = (1)/(6) *  (1)/(6) *  (1)/(6)  = (1)/(216)

Hence, the probability that Tania would pick a yellow bead on the first draw, then a blue bead, and finally a yellow bead again is 1/216.

Learn more about Probability:

brainly.com/question/795909

Answer 2
Answer: Each specific bead color has (each time) a probability \frac{1}6 of being drawn.

Hence the final probability is \frac{1}6\cdot\frac{1}6\cdot\frac{1}6=\boxed{(1)/(216)}

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Answers

Answer:

The answer is 1

Step-by-step explanation:

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Answer:

1

Step-by-step explanation:

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Answers

Answer:

7

Step-by-step explanation:

given the expression, we are expected to solve for the value of x

-(9x-4)+12+18x>79

we begin by opening the bracket

-(9x-4)+12+18x>79\n\n-9x+4+12+18x>79\n\n

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Answers

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Answers

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Answers

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question in the attached picture

Answers

1) x^(2) +2x-10=0
a=1
b=2
c=-10
x= \frac{-(2) +or-  \sqrt{ 2^(2)+4(1)(-10) } }{2(1)}
x= (-2 + or - √(4+40) )/(2)
x= (-2 +or- √(44) )/(2)
x= (-2+or- 2√(11) )/(2)
x= -1+or- √(11)
√(11)=3.32
-1+3.32 = 2.32
-1-3.32 = -4.32

2) 
x^(2) -2x-9=0
a=1
b=-2
c=-9
x= \frac{-(-2)+or- \sqrt{ (-2)^(2)+4(1)(-9) } }{2(1)}
x= (2+or- √(4+36) )/(2)
x= (2+or- √(40) )/(2)
x= (2+or-2 √(10) )/(2)
x=1+or- √(10)
√(10) =3.16
1+3.16 = 4.16
1-3.16 = -2.16

3) 
x^(2) -9x+5=0
a=1
b=-9
c=5
x= \frac{-(-9)+or- \sqrt{(-9)^(2)-4(1)(5) } }{2}
x= (9+or- √(81-20) )/(2)
x= (9+or- √(61) )/(2)
x= (9)/(2) +or-  ( √(61) )/(2)
√(61) = 7.81
(7.81)/(2) =3.91
(9)/(2)=4.5
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