a2 + 4a + 16
a2 + 14a + 49
a2 + 15a + 75
a2 + 26a + 169
The exactly two answers are correct are a² + 14a + 49 and a² + 26a + 169.
The condition for the perfect trinomials is if the coefficient of a² = 1 and If you divide the middle number coefficient by 2 and you square it you get the last term.
For all the options, the coefficient of a² = 1.
a² + 4a + 16.
Coefficient of a = 4.
4/2 = 2
2² = 4, this does not equal the last term so it is not a perfect square trinomial.
a² + 14a + 49.
Coefficient of a = 14.
14/2 = 7
7² = 49, this is equal to the last term so it is a perfect square trinomial.
And the perfect square is (a +7)²
Similarly, if you test the last option.
a² + 26a + 169.
Coefficient of a = 26.
26/2 = 13
13² = 169, this is equal to the last term so it is a perfect square trinomial.
And the perfect square is (a +13)²
The only two options are: a² + 14a + 49 and a² + 26a + 169. Other options do not pass this test.
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We can write the range of the function f(x) as -
Range → (- ∞, 4].
A function is a relation between a dependent and independent variable. We can write the examples of function as -
y = f(x) = ax + b
y = f(x, y, z) = ax + by + cz
Given is a parabola as shown in the image.
Range is the set of {y} values i.e. the values of the function f{x} in entire
domain of the function. So, from the definition of range, we can write the
range of the function as -
Range → (- ∞, 4].
Therefore, we can write the range of the function f(x) as -
Range → (- ∞, 4].
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Answer:
C. y < or = to 5
Step-by-step explanation:
the function stops at 5, so the numbers below are apart of the function, including 5. So, it is C.
have a great day
The second customer paid $60.00 for 2 bunches of roses and 5 bunches of daisies.
What was the cost, in dollars, of each bunch of roses?
(A) $8.25
(B) $9.50
(C) $10.00
(D) $12.00
Answer:c 10.00
Step-by-step explanation:
i just took the test lol
2.given the following equation solve for a.
(Assume a,b and c are positive real numbers)
My Conditional Frequency Question is:
My solution (work and answer):
Please explain how/why you chose this question
Therefore , the solution of the given problem of unitary method comes out to be the likelihood that a particular child has a curfew given that they have tasks is 3/7, or roughly 0.43.
The job can be completed by bringing together what was learned and applying this variable technique, that also includes all supplementary data from two people that utilized a specific tactic. To put it another way, if the desired outcome materialises, either the entity stated in the calculation will be recognised, or both expression essential processes will truly skip the colour. For forty pencils, a refundable charge of Rupees ($1.01) might be required.
Here,
Using the following formula, one can determine the conditional chance that a child will have a curfew if they have chores:
Curfew and duties are equal, so
=>P(curfew | chores) = P (chores)
The odds are listed in the table below:
=> Curfew and errands P = 3/10
=> P(tasks) = 7/9
Therefore,
=> P(curfew | chores)=3/10/ (7/10)=3/7
Therefore, the likelihood that a particular child has a curfew given that they have tasks is 3/7, or roughly 0.43.
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