formula represents a hydrocarbon. Therefore, option (2) is correct.
Hydrocarbons are merely carbon and hydrogen. Aliphatic or aromatic. Aliphatic hydrocarbons are saturated or unsaturated open-chain hydrocarbons.Saturated aliphatic hydrocarbons have single bonds, while unsaturated ones have double or triple bonds.
Aromatic hydrocarbons have alternating double bonds in a ring.Only option 2——is a hydrocarbon. Butane, a saturated aliphatic hydrocarbon, with four carbon and 10 hydrogen atoms.
Learn more about hydrocarbons, here:
#SPJ6
Test the niobium sample for the presence of niobium oxide compounds.
Heat the niobium, and see if the level of radioactivity in the lab increases.
Place the niobium under pressure, and see if the level of radioactivity in the lab increases.
A scientist can assess whether a pure niobium (Nb) sample is responsible for contaminating the lab with radioactivity by A. Testing the niobium sample to see whether it now contains other elements.
It should be noted that radioactivity simply means the natural process through which atoms disintegrate.
In this case, the scientist can assess whether a pure niobium (Nb) sample is responsible for contaminating the lab with radioactivity by testing the niobium sample to see whether it now contains other elements.
Learn more about radiation on:
#SPJ6
The initial volume of the gas is 117L.
Volume is the amount of space the matter occupies.
PV/T = k
where P = pressure, V = volume, T = absolute temperature in K and k= constant.
P1V1 / T1 = P2V2 / T2
Where P1 and P2 = initial and final pressure in atm
T1 and T2 = Initial and final temperature in K
V1 and V2 = initial and final volume in L
Using combined gas law:
P1V1/T1 = P2V2/T2
Given:
P1 = 0.5 atm
T1 = 325K
P2 = 1.2 atm
V2 = 48L
T2 = 320K
Assuming that the number of moles are constant for both conditions:
(P1 x V1)/T1 = (P2 x V2)/T2
Substituting the given values,
(0.5 x V1)/325 = (1.2 x 48)/320K
Solving for V1
V1 = (1.2atm x 48L x 325K)/ (320Kx 0.5 atm)
V1 = 117L
Hence, the initial volume of the gas is 117L.
To learn more about combined gas law here
#SPJ2
what happened millions of years ago
the time prior to the use of written records
2. Silver
3. Copper
4. Sulfur
Potassium is the element that is so active chemically that it occurs naturally only in compounds.
The element that is so active chemically that it occurs naturally only in compounds is potassium.
Potassium is a highly reactive alkali metal that is commonly found in nature bonded to other elements in compounds. It is not found in its pure form due to its reactivity.
An example of a compound that contains potassium is potassium chloride (KCl), which is commonly used as a salt substitute.
#SPJ11