What is a box and whisker plot in asking how often does store A have 300 or less customers per day?
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Answer:
Step-by-step explanation:
Let x be the no. of minutes
Plan A
Monthly rental = $12
Call charges for 1 minute = 7¢
1 cents = 0.01 dollars
So, Call charges for 1 minute = $0.07
Call charges for x minutes = 0.07 x
Total cost of Plan A = 12+0.07x
Plan B
Monthly rental = $15
Call charges for 1 minute = 5¢
1 cents = 0.01 dollars
So, Call charges for 1 minute = $0.05
Call charges for x minutes = 0.05 x
Total cost of Plan B = 15+0.05x
An inequality in terms of the number of minutes which shows when Plan A is less expensive than Plan B=
Solving the inequality :
So, the no. of minutes must be less than 150 for Plan A to be less expensive than Plan B
Hence an inequality in terms of the number of minutes which shows when Plan A is less expensive than Plan B is
B- 2.6
C- 8
D -4
Answer:
4,8,12,16,20,24,28,32,36,40,44,48,52,56,60,64,68,72,76,80,84,88,
Step-by-step explanation:
The amount of time his teammate have to catch the ball is equal to 1.774 seconds.
Given the following function:
In order to determine the amount of time his teammate have to catch the ball, we would evaluate the given position-time function as follows:
f(t) = -16t² + 25t + 6.
In Mathematics, the standard form of a quadratic equation is given by;
ax² + bx + c =0
Where:
a = -16.
b = 25.
c = 6.
Solving the function by using the quadratic formula, we have:
t = [-b ± √(b² - 4ac)]/2a
t = [-25 ± √[(25² - 4(-16)(6))]/2(-16)
t = [25/32 ± (-1/32)√1009]
t = 25/32 ± (-0.993)
t = 0.781 ± 0.993
t = 0.781 + 0.993
Time, t = 1.774 seconds.
Note: We ignored the negative value because time cannot be negative.
Read more on quadratic equation here: brainly.com/question/1214333
Answer:
B
Step-by-step explanation:
The verified dude saisd so
4. If you enter into an annual contract but decide to leave after 5 months, how much do your parents lose by not doing the month-to-month contract.
B. 3 : 5 = 12 : 20
C. 14 : 6 = 28 : 18
D. 42 : 7 = 6 : 2