Answer:
CP = 6
Step-by-step explanation:
The length of segment BC is given by the Pythagorean theorem:
AC² = AB² +BC²
(√61)² = 5² + BC² . . . . . fill in the given numbers
61 -25 = BC² = 36 . . . . .subtract 25
BC = 6 . . . . . . . . . . . . . . take the square root
Since the center of the circle is on AB and is tangent to BC, it must pass through point B. That is, segment BC of length 6 is one of the tangent lines from point C. The other one, to point P, must be the same length, so ...
CP = 6
Answer:
$89.7
Step-by-step explanation:
We are given with
height = 9 feet
length = 10 feet
wall brackets:
48-in costing $12.95
60-in costing $16.95
distance of brackets from ends = 1 foot
maximum distance between brackets= 24 inches
The brackets are
48/12 = 4 feet
and
60/12 = 5 feet
One of each must be used to cover the height of the shelf
The length of the shelf is
60 inch
subtracting 1 in from each side for the allowance
60 - 2 = 58 in
Dividing by 24 inches
58/24 = 2.41 ~ 3
The total cost is
($12.95 + $16.95) * 3 = $89.7
The total cost of the brackets is $89.7
I think is twelve cause June may so ya Answer:
Step-by-step explanation:
21 vueltas y Evelyn: 1650 m. ¿Cuántos metros corrieron Juanita y Esperanza?
¿Y cuántas vueltas dio Evelyn?
Answer:
Juanita and Esperanza run 400 meters and 8400 meters respectively and Evelyn make 4.125 laps.
Step-by-step explanation:
The complete question is: A telesecundaria school has a race track that measures one kilometer.
Three students ran the following distances Juanita: 1 laps, Esperanza 21 laps and Evelyn: 1650 m. How many meters did Juanita and Esperanza run? And how many laps did Evelyn make?
As we know that 1 meter = 0.0025 laps
So, the number of laps Evelyn make = 1650 0.0025
= 4.125 laps
Also, 1 lap = meters
1 lap = 400 meters
So, the meters that Juanita run = 1 400 = 400 meters
Similarly, the meters that Esperanza run = 21 400
= 8400 meters
Hence, Juanita and Esperanza run 400 meters and 8400 meters respectively and Evelyn make 4.125 laps.
Juanita ran 1 kilometer and Esperanza ran 21 kilometers. Evelyn ran 1 lap.
To find out how many meters Juanita and Esperanza ran, we need to add up their distances. Juanita ran 1 lap, which is equal to the length of the track. Since the track is 1 kilometer long, Juanita ran 1 kilometer. Esperanza ran 21 laps, so she ran 21 kilometers.
Evelyn ran 1650 meters. To find out how many laps Evelyn ran, we need to divide 1650 by the length of the track. Since the track is 1 kilometer long, Evelyn ran either 1 lap or 1.65 laps. However, we're told that Evelyn ran 1650 meters, so she ran 1 lap.
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