The formula for specific gravity is:
where is the density of the substance and is the density of water.
The density of water, =
Substituting the values in above formula we get,
The formula of density is:
The density of mercury is
The mass of mercury is
Substituting the values in density formula:
The amount, in milliliters, of mercury that will have a mass of 0.35 kg would be 25.74 mL.
If the specific gravity of mercury is 13.6, the density can be obtained such that:
Density of mercury = specific gravity of mercury/density of water
The density of water is 1 g/mL. Thus:
Density of mercury = 13.6/1
= 13.6 g/mL
Also; density = mass/volume
volume = mass/density
= 350/13.6
= 25.74 mL
Thus, the number of milliliters of mercury that will have a mass of 0.35 kg would be 25.74.
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Boyle's law deals with pressure and volume.
Robert Boyle studied the relationship between the pressure p and the volume V of a confined gas held at a constant temperature.
Boyle observed that the product of the pressure and volume are observed to be nearly constant.
The product of pressure and volume is exactly a constant for an ideal gas.
PV = constant
As per Boyle’s law, any change in the volume occupied by a gas (at constant quantity and temperature) will result in a change in the pressure exerted by it. In other words, the product of the initial pressure and the initial volume of a gas is equal to the product of its final pressure and final volume (at constant temperature and number of moles).
Therefore, Boyle's law deals with pressure and volume.
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The percentage of nitrogen in nitrous oxide or N₂O is 63.64% and percent of oxygen is 36.36 %.
It is the percent of each element which exists in a compound. It is calculated in three methods:
1) percent w/w
2) percent v/v
3) percent w/v
Percent w/w is the percent composition wherein both the components are solids.Percent v/v is percent composition wherein the 2 substances are liquid and percent w/v is percent composition where one substance is solid and one is in liquid form.
The percent composition of all substances is equal to 100%.The percent composition of nitrogen in nitrous oxide is calculated as follows:
molar mass of nitrous oxide=44 g
molar mass of nitrogen =14 g
As nitrous oxide has 2 nitrogen ,therefore 14×2=28
To find percent composition,
molar mass of nitrogen in nitrous oxide/molar mass of nitrous oxide×100
∴28/44×100=63.64%
Thus, percent of nitrogen in N₂O is 63.64%.
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Answer:
63.64% Nitrogen
36.36 Oxygen
b) the metals strips
c) amount of rust
d) hydrochloric acid
Answer:
b) the metals strips
Explanation:
In an experimental design, an independent variable is a variable that is changed or manipulated in a series of experiments. An independent variable is not dependent on any other variable in the experiment. The hypothesis for this experiment is stated to be: "If the chemical activity of the metallic wrapper is increased, then less rusting of iron will occur. The independent variable relates to the type of metal wrapping strip, and the dependent variables are the amount of rusting and color of the water.