B. T=273K and P=0.25 atm
C. T=300k and P=2 atm
D. T=273K and P=2 atm
Answer:
help me please
Explanation:
Answer:
atoms remain bonded to each other in physical changes.
Explanation:
Answer:
c
Explanation:
Answer:
1069.38 gallons
Explanation:
Let V₀ = 1.07 × 10³ be the initial volume of the gasoline at temperature θ₁ = 52 °F. Let V₁ be the volume at θ₂ = 97 °F.
V₁ = V₀(1 + βΔθ) β = coefficient of volume expansion for gasoline = 9.6 × 10⁻⁴ °C⁻¹
Δθ = (5/9)(97°F -52°F) °C = 25 °C.
Let V₂ be its final volume when it cools to 52°F in the tank is
V₂ = V₁(1 - βΔθ) = V₀(1 + βΔθ)(1 - βΔθ) = V₀(1 - [βΔθ]²)
= 1.07 × 10³(1 - [9.6 × 10⁻⁴ °C⁻¹ × 25 °C]²)
= 1.07 × 10³(1 - [0.024]²)
= 1.07 × 10³(1 - 0.000576)
= 1.07 × 10³(0.999424)
= 1069.38 gallons
To calculate the amount of gasoline that can be poured into the tank, we need to find the change in volume of the gasoline when its temperature changes from 97.0°F to 52.0°F. Using the equation for volume expansion, we can calculate this change in volume to be approximately 258 gallons.
To calculate the amount of gasoline that can be poured into the tank, we need to find the change in volume of the gasoline when its temperature changes from 97.0°F to 52.0°F. We can use the equation for volume expansion to calculate this change in volume:
ΔV = V₀ * β * ΔT
Where ΔV is the change in volume, V₀ is the initial volume, β is the coefficient of volume expansion, and ΔT is the change in temperature.
In this case, the initial volume V₀ is 1.07 * 10³ gallons, the coefficient of volume expansion β is 9.6 * 10⁻⁴ (°C)⁻¹, and the change in temperature ΔT is (52.0°F - 97.0°F) = -45.0°F.
Converting the change in temperature to Celsius: ΔT = (45.0°F) * (5/9) = -25.0°C.
Plugging in these values into the equation, we get:
ΔV = 1.07 * 10³ * 9.6 * 10⁻⁴ * -25.0 = -258 gallons.
Therefore, when the gasoline is poured into the tank, approximately 258 gallons will be poured out of the truck.
#SPJ3
Refrigerator
Counter
CO
The kitten's gravitational potential energy on top of the refrigerator is greater, but what is the kitten's gravitational
potential energy on top of the counter? Assume gravity as 10, if needed.
Answer:
E = 27 J
Explanation:
It is given that,
Mass of a kitten is 1.5 kg
Initially, it was at a height of 1.8 m refrigerator and finally jumps to a 0.9 m height counter.
We need to find the kitten's gravitational potential energy on top of the counter. Potential energy is possessed due to the position of an object. It can be given by :
g is acceleration due to gravity
So, the kitten's gravitational potential energy on top of the counter is 27 J.