Which substance is an Arrhenius acid?
(1) LiF(aq) (3) Mg(OH)2(aq)
(2) HBr(aq) (4) CH3CHO

Answers

Answer 1
Answer:

Answer: Option (2) is the correct answer.

Explanation:

Arrhenius acid are the species that donate a H^(+) ion or proton.

For example, HBr \rightarrow H^(+) + Br^(-)

Whereas LiF, Mg(OH)_(2), and CH_(3)CHO are the substances which do not give a proton upon dissociation. Hence, they are not Arrhenius acids.

Therefore, we can conclude that HBr(aq) substance is an Arrhenius acid.

Answer 2
Answer: HBr (aq) is an Arrhenius acid.
The equation is HBr(aq) -> H+ + Br- 

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Which of the following statements is true for an exothermic reaction? The products have higher potential energy than the reactants, and the enthalpy change is negative. The products have higher potential energy than the reactants, and the enthalpy change is positive. The products have lower potential energy than the reactants, and the enthalpy change is negative. The products have lower potential energy than the reactants, and the enthalpy change is positive.
Central American countries are important agricultural producers. Each year, the United States imports about five billion dollars’ worth of __________.a. bananasb. cacaoc. mangoesd. coffee
A yellow luminous flame is produced when an insufficient amount of oxygen is supplied. This flame should not be used when heating because it will coat glassware with black soot. What element is this made from? Answer with the correct elemental symbol. It will be case sensitive.
The chemical bonding in sodium phosphate, Na3PO4, is classified as:

Henri Becquerel discovered radium and polonium.Please select the best answer from the choices provided
T
F

Answers

That would be false, Marie Curie discovered radium and polonium.

Answer:

That would be false

Explanation:

No need to explain

At equilibrium, a sample of gas from the system is collected into a 4.00 L flask at 600 K. The flask is found to contain 3.86 g of PCl₅, 12.7 g of PCl₃, and 13.3 g of Cl₂. What are the values of Kc and Kp for this reaction?

Answers

Answer:

Explanation:

                                             PCl₅    ⇄    PCl₃    +     Cl₂

                                           1 mole         1 mole        1 mole

molecular weight of  PCl₅ = 208.5

molecular weight of PCl₃  = 137.5

molecular weight of Cl₂  =       71

moles of PCl₅ = .0185

moles of PCl₃ = .0924

moles of Cl₂ = .1873

Total moles = .2982 moles

mole fraction of PCl₅ = .062

mole fraction of  PCl₃ = .31

mole fraction of Cl₂ = .628

If total pressure be P

partial pressure of  PCl₅ = .062 P

partial pressure of  PCl₃ = .31 P

partial pressure of  Cl₂ = .628 P

Kp = .31 P  x  .628 P /  .062 P

= 3.14 P

To calculate Total pressure P

PV = nRT

P x 4 x 10⁻³ = .2982 x 8.31  x 600

P = 371.7 x 10³

= 3.717 x 10⁵ Pa

Kp = 3.14 P = 3.14 x  3.717 x 10⁵ Pa

= 11.67 x 10⁵ Pa

Kp  = Kc x ( RT )^(\triangle n)

\triangle n = 1

11.67 x 10⁵ = Kc x ( 8.31* 600 )^(1)

Kc = 234

When fossil fuels are burned, _____ is released into the atmosphere.A. oxygen
B. nitrogen
C. ammonia
D. carbon dioxide

Answers

Carbon dioxide. This is because when fossil fuels are burned, oxygen combines with carbon to form CO2 and with hydrogen to form water (H2O). These reactions release heat that we use for energy. For example, for the same amount of energy produced, burning natural gas produces about half of the amount of CO2 produced by burning coal.

Final answer:

The burning of fossil fuels primarily releases carbon dioxide into the atmosphere, contributing to greenhouse gas emissions and global warming.

Explanation:

When fossil fuels are burned, carbon dioxide (CO₂) is predominantly released into the atmosphere. Fossil fuels, such as coal, oil, and natural gas, are composed mainly of carbon. During combustion, this carbon combines with oxygen in the air to form carbon dioxide. This process is a significant source of greenhouse gases, contributing heavily to global warming. It's important to note that other substances like water vapor and minor amounts of sulfur oxides can also be produced in this reaction, but the main product is carbon dioxide.

Learn more about Burning of Fossil Fuels here:

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The length of time required for half of the radioactive atoms in a sample to decay is its. A. half-life. . B. relative date. . C. radioactive date. . D. period.

Answers

The length of time required for half of the radioactive atoms in a sample to decay is its half-life. The correct option among all the options that are given in the question is the first option or option "A". The other choices are incorrect and can be easily neglected. I hope that this is the answer that has come to your help.

What is the maximum number of orbitals in a p sublevel? a. 2
b. 3
c. 4
d. 5

Answers

Answer:

b. 3

Explanation:

Each level has its electrons distributed in different sub-levels, which can be of four types: s, p, d, f

In each sub-level, there is a certain number of orbitals that can contain a maximum of 2 electrons each.

For example, the sub-level s can only contain 2 electrons, therefore it has only one orbital.

The sub-level p can contain 6 electrons, and since each orbital can contain a maximum of 2 electrons it means that the sub-level p has 3 orbitals.

b.3 is what i believe from what i read

PLEASEEE HELPP!!! Select all the correct answers. Which compounds have the empirical formula CH2O?

A.C2H4O2

B.C3H6O3

C.CH2O2

D.C5H10O5

E.C6H12O6

Answers

Answer: Compounds having the same empirical formula CH_2O are:

C_2H_4O_2,C_3H_6O_3,C_5H_(10)O_5,C_6H_(12)O_6

Explanation:

Empirical formula tells us about the proportion of the elements present in the compound but it do not tells us about the actual numbers of atoms of the elements present in the compound.

In given empirical formula CH_2O that is proportion of  C:H:O = 1:2:1

In C_2H_4O_2 the proportion of C:H:O =2:4:2= 1:2:1

In C_3H_6O_3 the proportion of C:H:O =3:6:3= 1:2:1

In CH_2O_2 the proportion of C:H:O =1:2:2= 1:2:2

In C_5H_(10)O_5 the proportion of C:H:O =5:10:5= 1:2:1

In C_6H_(12)O_6 the proportion of C:H:O =6:12:6= 1:2:1

Compounds having the given empirical formula CH_2O are:

C_2H_4O_2,C_3H_6O_3,C_5H_(10)O_5,C_6H_(12)O_6

The chemical compounds that have the empirical formulaCH_2O are:

A.C2H4O2

B.C3H6O3

D.C5H10O5

E.C6H12O6

An empirical formula can be defined as a formula that gives the smallest and simplest whole number ratio of the atoms of a chemical element found in a chemical compound.

The simplest whole number ratio of the atoms of  CH_2O is:

CH_2O = 1:2:1

  • 1 atom of carbon.
  • 2 atoms of hydrogen molecule.
  • 1 atom of oxygen.

For C_2H_4O_2:

C_2H_4O_2 = 2:4:2 = 1:2:1

For C_3H_6O_3:

C_3H_6O_3 = 3:6:3 = 1:2:1.

For CH_2O_2:

CH_2O_2 = 1:2:2 = 1:1:1  (Incorrect)

For C_5H_(10)O_5:

C_5H_(10)O_5 = 5:10:5 = 1:2:1

For C_6H_(12)O_6:

C_6H_(12)O_6 = 6:12:6 = 1:2:1

Note:

  • C is the chemical symbol of carbon.
  • H is the chemical symbol of hydrogen.
  • O is the chemical symbol of oxygen.

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