Which terms are used to identify pure substances?(1) an element and a mixture
(2) an element and a compound
(3) a solution and a mixture
(4) a solution and a compound
Answers
Answer is: (2) an element and a compound.
Pure substance is made of only one type of atom (element) or only one type of molecule (compound), mixtures and solutions are made from two or more types of pure substances.
Elements (for example copper, iron, sulfur) and compounds (water, sodium chloride) have definite and constant composition with distinct chemical properties.
Pure substances can be separated chemically, not physically, that is difference between pure substances and mixtures.
Related Questions
The true color of water isa. clear.b. greenish blue.c. sky blue.d. green. E. white.
How does the number of molecules in 1 mol of oxygen compare with the number of molecules in 1 mol of nitrogen?1) 1 mol of oxygen has fewer molecules.2) 1 mol of oxygen has more molecules.3) Each sample has the same number of molecules.4) The molecules cannot be compared without knowing the mass.
Given the balanced equation representing a reaction occurring in an electrolytic cell:
State the use of multimeters
B. He gave them names and properties and placed them in the table.
C. He created them in his laboratory and placed them in the table.
D. He ignored them, placing them in the table and shifting others when they were discovered. 2. Which of the following elements have properties similar to those of astatine (At)? A. F, Br, I B. Ar, S, P C. F, Ar, Ne D. Na, Mg, Al 3.What is true of the ionic size of the elements in a group as one moves from top to bottom in that group?
A. Ionic size stays the same within the group.
B. Ionic size does not vary in any predictable way within the group.
C. Ionic size decreases from top to bottom within the group.
D. Ionic size increases from top to bottom within the group.
Answers
He couldn't just just imagine index and go with a flow, he left space for it in order to dicrover it through reactions.
What about the next question, the answer is A. F, Br, I, its properties similar to those of astatine (At).
The last one :D. Ionic size increases from top to bottom within the group.
sample was gray, non-metallic, had
density of 3.8 g/mL, and a volume
of 48.3 mL
Of the observed properties listed
below, which is considered to be an
extensive property?
A Gray
B Metallic
C Density
D Volume
Answers
Answer:
D. Volume
Explanation:
Properties mentioned in the question;
colour = gray
Nonmetallic
Density = 3.8 g/mL
Volume = 48.3 mL
Of the mentioned, which is extensive ?
Extensive properties are those properties that are proportional to the amount of substance present.
The correct option is D. Volume. The other properties do not change with increasing or decreasing amount of the mineral
Final answer:
Volume is considered to be an extensive property.
Explanation:
The extensive property out of the observed properties listed is volume. An extensive property is one that depends on the amount of a substance. In this case, the volume of the mineral sample is directly proportional to the amount of the sample, so it is considered an extensive property.
Learn more about Extensive property here:
#SPJ3
(1) O2
(2) CO2
(3) NH3
(4) CH4
Answers
Answer: Option (3) is the correct answer.
Explanation:
A molecule is polar when the net dipole moment of molecule is zero. When an electronegative atom is attached to an electropositive atom then the electronegative atom pulls the shared pair of electrons more towards itself.
As a result, the movement of electrons is more towards the electronegative atom and the dipole moment becomes zero. This will also induce partial positive and partial negative charge on electropositive and electronegative atom.
On the other hand, are covalent compounds and does not have a net zero dipole moment.
Thus, we can conclude that out of the given options represents a polar molecule.
Answers
Given:
128g sample of titanium
2808J of heat energy
specific heat of titanium is 0.523 J/ g °C.
Required:
Change in temperature
Solution:
This can be solved through the equation H = mCpT where H is the heat, m is the mass, Cp is the specific heat and T is the change in temperature.
Plugging in the values into the equation
H = mCpT
2808J = (128g) (0.523 J /g °C) T
T = 41.9 °C
Bromine +
Chlorine
Bromide +
Potassium
Chloride
Bromine +
Potassium
Chloride
Hydrogen
bromide +
Potassium
Chloride
Chlorine +
Potassium
Bromide ->
Answers