CHEMISTRY HIGH SCHOOL

Under which conditions of temperature and pressure would a sample of H2(g) behave most like an ideal gas?(1) 0°C and 100 kPa
(2) 0°C and 300 kPa
(3) 150°C and 100 kPa
(4) 150°C and 300 kPa

Answers

Answer 1
Answer: 3). 150°C and 100 kPa


Gases behave ideally at high temperatures and low pressures (less intermolecular forces)

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Iron(III) oxide + carbon yields carbon monoxide and iron (write the correct formulas and then balance)

Answers

Iron(III) oxide  =  Fe₂O₃
Carbon  =  C
Carbon monoxide  =  CO
Iron  =  Fe

Fe₂O₃ + C ⇒ CO + Fe

These are the correct formulas, but the equation is not balanced.  There are two Fe's on the left side, so we have to put a 2 in front of the Fe on the right.  Also, there are 3 O's on the left but only 1 on the right, so we need to put a 3 in front of the CO; however, this 3 makes it 3 C's on the right, so we balance that off by putting a 3 in front of the C on the left:

Fe₂O₃ + 3C ⇒ 3CO + 2Fe
Fe(coeffecient 2)O(coeffecient 3) +3C=3CO+2Fe is the balanced equation

An atom is determined to contain 12 protons, 10 electrons, and 12 neutrons. What are the mass number and charge of this atom or ion? Select one:
a. mass number: 24, charge: +2
b. mass number: 22, charge: neutral
c. mass number: 34, charge: -2
d. mass number: 34, charge: +2

Answers

The mass mass number is 22 and the charge of the atom is +2. The correct answer is option A

How to determine the mass number and charge?

1. The mass number of the atom can be obtained as follow:

  • Number of protons = 12
  • Number of neutrons = 12
  • Mass number =?

Mass number = number of proton + number of neutron

= 12 + 12

= 24

2. The charge of the atom can be obtained as follow:

  • Number of protons = 12
  • Number of electrons = 10
  • Charge =?

Charge = number of protons - number of electrons

= 12 - 10

= +2

Thus, the mass number is 24 and the charge is +2. The correct answer to the question is option A

Learn more about mass number:

brainly.com/question/29284261

#SPJ6
Mass number= atomic number + number of  neutrons.
A=Z+N
Z=number of protons=12
N=12

A=12+12=24

If, we have 12 protons and 10 electrons, the charge of this ion is +2

Therefore: mass number:24; charge: +2

Answer: a. mass number: 24; charge: +2

Rainforests are typically responsible for global oxygen turnover

Answers

false...........................................

Answer:

false

Explanation:

How many dozen of eggs are there in 3500 eggs?

Answers

3500/12 = exactly 291 and 2/3 dozen.
291 & 2/3 dozen are in 3500 eggs

How do you balance __H2SO4 + __B(OH)3 --> __B2(SO4)3 + __H2O

Answers

B(OH)_3=H_3BO_3

then

H_2SO_4+H_3BO_3\longrightarrow~B_2(SO_4)_3+H_2O

\boxed{3H_2SO_4+2H_3BO_3\longrightarrow~B_2(SO_4)_3+6H_2O}

1 point14. Which factor is not needed hen calculating the velocity of a satellite
orbiting a planet?
the mass of the satellite
the orbital radius of the satellite
the mass of the planet
the universal gravitational constant
Pls help I will give extra points

Answers

The mass of the satellite is not required when calculating the velocity of a satellite  orbiting a planet.

Given that the centripetal force on the satellite is;

F = mv^2/r

Where;

F = centripetal force that keeps the satellite in its orbit

m = mass of the satellite

r = radius of the satellite

Since the force of gravity and the centripetal force both act on the satellite and they are exactly balanced;

F = GMm/r^2

Where;

G = gravitational constant

M = mass of the planet

m = mass of the satellite

r = radius of the satellite

Hence;

F = GMm/r^2 = mv^2/r

GMm/r^2 = mv^2/r

v = √GM/r

Thus, the mass of the satellite is not required when calculating the velocity of a satellite  orbiting a planet.

Learn more: brainly.com/question/21454806

Answer:

i. the mass of the satellite will not be required in this calculation

Explanation:

When a satellite is orbiting a planet, it experiences two forces. The centripetal force and the gravitational force that the planet exerts on the satellite. In order for the satellite to keep in orbit, the centripetal force and the gravitational force must be equal.

The expression for the centripetal force is:

F_c = (m_s)v² / R

where

m_s is the mass of the satellite

R is the radius of the satellite's orbit

v is the velocity that the satellite travels with around the planet

The expression for the Gravitational force is:

F_g = (G M_p m_s) / R²

where

G is the universal gravitational constant

M_p is the mass of the planet

m_s is the mass of the satellite

R is the radius of the satellite's orbit

Thus, equating the two forces together, we get:

(G M_p m_s) / R² = (m_s)v² / R

We can cancel out m_s since it is a common factor on both sides.

Thus,

(G M_p) / R² = v² / R ⇒ M_p = v²R / G

Therefore, the mass of the satellite is not required to calculate the mass of the planet.

Explanation:

Hope this helps:)
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