The longest flagpole that could be shipped in a box that measures 2 ft by 2 ft by 12 ft is 2 feet long.
To find the minimum of a continuous and twice differentiable function f(x), we can firstly differentiate it with respect to x and equating it to 0 will give us critical points.
Putting those values of x in the second rate of function, if results in negative output, then at that point, there is maxima. If the output is positive then its minima and if its 0, then we will have to find the third derivative (if it exists) and so on.
We are given that;
The measurement of box= 2*2*12ft
Now,
To determine the longest flagpole that could be shipped in a box that measures 2 ft by 2 ft by 12 ft, we need to find the maximum length of a flagpole that can fit inside the box without exceeding any of the box's dimensions.
The longest flagpole that could fit inside the box would be equal to the shortest dimension of the box, which is 2 feet. This is because the flagpole would need to fit inside the box in a diagonal orientation in order to maximize its length.
Therefore, by the maxima and minima answer will be 2 feet long.
Learn more about maxima and minima of a function here:
#SPJ3
Answer:
San Fransisco
Step-by-step explanation:
If Geneva is 12°C colder than her hometown, this means that her hometown is 12°C warmer than -3°C.
Since warmer means a higher number, we find 12 + -3, which is 9°C.
The town that is 9°C is San Fransisco.
The correct answer is B.
Hope this helps.
The average temperature change per hour is -3 degrees C
9(15) / 5 + 32
135 / 5 + 32
27 + 32
59
Answer:
9 and 3.35 respectively
Step-by-step explanation:
Mean=Sum of data÷No. of data
=(3+5+6+9+11+12+17)÷7
=63÷7
=9
Standard Deviation=√{(sum of squares of data÷no. of data)-(sum of data÷no. of data)
=√(705÷7)-(63÷7)
=√100.71÷9
=√11.19
=3.35
Answer:
d = 4
Step-by-step explanation:
Given
5d = - 4 + 6d ( subtract 6d from both sides )
- d = - 4 ( multiply both sides by - 1 )
d = 4