CHEMISTRY HIGH SCHOOL

In an experiment, 2.54 grams of copper completely reacts with sulfur, producing 3.18 grams of copper(I) sulfide.Determine the total mass of sulfur consumed.
Write the chemical formula of the compound produced.

Answers

Answer 1
Answer:

Answer:

               0.64 g of S

Solution:

               The balance chemical equation is as follow,

                                           2 Cu + S ----> Cu₂S

According to equation,

                        127 g (2 mole) Cu produces = 159 g (1 mole) of Cu₂S

So,

                                 2.54 g Cu will produce = X g of Cu₂S

Solving for X,

                     X = (2.54 g * 159 g) / 127 g

                     X = 3.18 g of Cu₂S

Now, it is confirmed that the reaction is 100% ideal. Therefore,

As,

                       127 g (2 mole) Cu required = 32 g (1 mole) of S

So,

                                2.54 g Cu will require = X g of S

Solving for X,

                      X = (2.54 g * 32 g) / 127 g

                      X = 0.64 g of S
Answer 2
Answer:

Answer : The total mass of sulfur consumed will be, 0.64 grams and the chemical formula of the compound produced is, Cu_2S copper oxide.

Solution :

According to the law of conservation of mass, the total mass of reactant should be equal to the total mass of product.

The balanced chemical reaction will be,

2Cu+S\rightarrow Cu_2S

In this reaction, copper and sulfur are the reactants and copper sulfide is the product.

Let the mass of sulfur be 'x' gram

\text{The total mass of reactants}=\text{Total mass of copper}+\text{Total mass of sulfur}=2.54g+x

\text{The total mass of product}=\text{Total mass of copper sulfide}=3.18g

According to the law of conservation of mass,

\text{The total mass of reactants}=\text{The total mass of product}

2.54g+x=3.18g

x=(3.18-2.54)g

x=0.64g

Therefore, the total mass of sulfur consumed will be, 0.64 grams and the chemical formula of the compound produced is, Cu_2S copper oxide.

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A sample of salt (sodium chloride) is placed on the tip of a platinum wire. When the sample is heated on blue flame the flame turned yellow. Explain how this can be done to electrons in sodium atoms

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So platinum is a transition metal. In general transition metals are reducers, which means they can give the electrons they have, to the sodium atoms. Also in chemistry we look at sub orbitals rather that shells(2,8,8). So due to the energy from heat, the d orbital split as electrons move to a higher energy level. Some of the electrons are given to the sodium ions and therefore the flame changes colour to yellow. 
The excitation of the electrons is caused by them getting energy and so moving up an energy level. This energy is released and the electron returns to it's original state. The energy released, however, does not release in the same direction, but in different/various directions. Therefore the colour of the light changes as some energy is released in the surrounding.

The density of an object is defined as mass per unit volume. Mathematically we write that: D = M/V. Rearrange this expression for: (a) M = ? (b) V = ?

Answers

The density of an object is defined as mass per unit volume. This can be rearranged to determine the mass or the volume of an object. For mass, the expression of density is rearranged to: M = VD. For the volume, the density is rearranged to: V = D/M.

Write M if the unit is that of a mass, V if the unit is that of a volume,and D if the unit is that of a density.

Answers

Answer:

6) V     7) M     8) V     9) D     10) D     11) M     12) D     13) V

Explanation:

Volume- cm^3, ml, etc.

Mass- g/cm^3, g/ml, etc.

Density- g, kg, etc.

The ph of a buffer does not depend much on the concentrations of its acid–base conjugate pair because

Answers

Answer:

It could react with the present hydride or hydroxile ions.

Explanation:

Hello,

One the main features of buffers, is that when the acid-base conjugates are formed they could react with the added H^+ or OH^(-1) in order to keep the pH as constant as its buffer capacity allows it.

Best regards.

Final answer:

A buffer solution maintains a stable pH primarily through the action of its acid-base conjugate pair reacting to counter changes, a property known as buffer capacity. High concentrations increase buffer capacity, allowing more acid or base to be neutralized. However, exceeding the buffer capacity can lead to pH changes.

Explanation:

The pH of a buffer solution doesn't greatly depend on the concentrations of its acid-base conjugate pair as the buffer's job is to keep the pH relatively constant. This is achieved by having appreciable amounts of its weak acid–base pair in the solution. If a strong acid or base is introduced into the system, the buffer pair reacts to counteract these changes. This is called buffer capacity.

For instance, consider a buffered solution composed of acetic acid and its conjugate base, acetate. The system can resist changes in pH upon addition of small quantities of an acid or base. This is because acetic acid and acetate can consume small additions of hydrogen ions (from an acid) or hydroxyl ions (from a base), keeping the overall pH stable.

When concentrations of the acid-base pair are high, the buffer capacity increases and hence more amounts of acid or base can be neutralized without a significant change in pH. However, there are limits to this capacity. If excessive amounts of acid or base are added, they may exceed the buffer's capacity, and its acid/base pairs will be either largely consumed or overrun, leading to changes in pH.

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Which of the following is an example of a Brønsted-Lowry base?​

Answers

Final answer:

A Brønsted-Lowry base is a species that accepts a proton (hydrogen ion) from another species. NH3, OH-, and even water itself are examples of Brønsted-Lowry bases, denoting they accept protons.

Explanation:

A Brønsted-Lowry base is a species that can accept a proton (a hydrogen ion) from another species. For instance, in a reaction between water and ammonia, NH3 is the Brønsted-Lowry base because it accepts a proton from water. This means that any species capable of accepting a proton, such as hydroxide ion (OH-), ammonia (NH3), or water itself can be considered a Brønsted-Lowry base.

For example, think about the dissociation of water:
H2O + H2O ⇌ H3O+ + OH-
In this reaction, water is acting as both a Brønsted-Lowry acid and a Brønsted-Lowry base. One water molecule donates a proton and becomes a hydroxide ion (the conjugate base), while the other accepts a proton to become hydronium (the conjugate acid).

Another example would be the ionization of ammonia in water:
NH3 + H2O ⇌ NH4+ + OH-
Here, ammonia (NH3) is the Brønsted-Lowry base as it accepts a proton from water to become ammonium (NH4+).

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Please help!!! Thank youuu I’ll give brainlist to first to get them right

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